Answer: Line graphs are used to track changes over short and long periods of time. When smaller changes exist, line graphs are better to use than bar graphs. Line graphs can also be used to compare changes over the same period of time for more than one group.
Explanation:
Answer:
B
Explanation:
since the impulse is moving form Q to P ...Q will be the receptor and P is the relay neuron which will transfer the impulse to the next neuron
Answer:
2. The white patches are caused by the deacetylation of the histones associated with the DNA of the w + allele.
3. The red patches are caused by the acetylation of the histones associated with the DNA of the w + allele.
Explanation:
The complete question is as follows:
How might one explain position-effect variegation in terms ofhistone acetylation and/or deacetylation? Select all thatapply.
1. The white patches are caused by the acetylation of the histonesassociated with the DNA of the w + allele.
2. The white patches are caused by the deacetylation of thehistones associated with the DNA of the w + allele.
3. The red patches are caused by the acetylation of the histonesassociated with the DNA of the w + allele.
4. The red patches are caused by the deacetylation of the histonesassociated with the DNA of the w + allele.
In the W+/W State variegated eye is produced, however in reality the W+ allele causes a red eye colour whereas the W allele causes a white eye.
The reason for production of variegated eyes is chromosomal rearrangement.
Due to the chromosomal rearrangement the W+ gene's position gets changed and it moves from a region of euchromatin to heterochromatin and this position affect leads to red and white patches in the eye.
The heterochromatin is silent region of the genome which does not encode for any product and this is caused by histone deacetylation whereas the histone acetylation makes the chromosomes more accessible and contributes the euchromatin region.
Answer:
The recombination frequency between two genes can not be more than 50 percent due to the independent and random assorting of the genes that are linked generating 50% recombination.
* Genes should be located far enough from one another so that crossover points can be made.
Example: Genes present at the 2 extreme ends of the chromosome.
* There should not be the linkage between the two genes due to linked genes go together. So no recombination happens.
It may be more than 50% if selected parents are heterozygous. But Mendel took homozygous parents. So, the maximum is 50%. There will be no recombinant if the two genes are linked.
Answer:
the animals that are selected for breeding will mix their DNAs while making the baby, so the baby will carry the characteristics of both parents (it depends on if the trait is dominant or recessive
Explanation:
