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Anna35 [415]
3 years ago
15

For which inequality is x = 7 a solution?

Mathematics
1 answer:
frosja888 [35]3 years ago
7 0
My teacher said A and C
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Find the length of the arc intercepted by a central angle calculator in pi
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4 years ago
Find the least common denominator. Then express each fraction using the least common denominator.
Rudiy27

Answer:

THE LCM OF 15 AND 20 IS 60

1/60 AND 3/60

Step-by-step explanation:

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3 years ago
Adrian has 34.5 feet of rope adrain uses 10.72 feet to make a swing how much rope left to left over after making the swing
Natasha_Volkova [10]

Answer:

23.78

Step-by-step explanation:

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3 years ago
a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
12345 [234]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

6 0
3 years ago
PLEASE HELP ASAP!!!
spayn [35]

Answer:

Mark made 15 shots

Step-by-step explanation:

Both made 60% of their shots

8 0
3 years ago
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