Ask question

Ask question

All categories

3 years ago

11

Elliot wrote a computer program that randomly generates a number from 2 to 10. If he runs the program twice, what is the probabi

lity that the number generated both times is a prime number?

2 answers:

masha68 [24]3 years ago

6 0

Answer:

16/81

Step-by-step explanation:

Charra [1.4K]3 years ago

5 0

Answer:

16/81

Step-by-step explanation:

i just did the assignment!!

You might be interested in

10. The lengths of the electrical extension cords in a workshop are 6 ft, 8 ft, 25 ft, 8 ft, 12 ft, 50 ft, and 25 ft. What are t

Setler79 [48]

First, let's find the mode since It's the one with the different options among the answer choices. So the numbers that repeat are 8 and 25, so in order to find the in inches, you'd have to multiply that by 12.
8 x 12 = 96
25 x 12 = 300
Therefore, your answer is A.

6 0

3 years ago

A movie rental website charges $5.00 per month for membership and $1.25 per movie.

denis-greek [22]

To solve this problem, I would transfer this word problem into an equation with variables.

let the variable m stand for the amount of movies andrew rents.

5.00+1.25m=16.25

Now that we have our equation, we can just solve it like any other equation.
To do this, first, we would subtract 5.00 from both sides, resulting in the equation

1.25m=11.25

Next, we would divide both sides by 1.25, resulting in your final answer

m=9.

This means that Andrew rented 9 movies if his total was 16.25

4 0

4 years ago

Assume that the Poisson distribution applies to the number of births at a particular hospital during a randomly selected day. As

kakasveta [241]

Answer:

0.9999985 = 99.99985% probability that in a day, there will be at least 1 birth.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Assume that the mean number of births per day at this hospital is 13.4224.

This means that $\mu = 13.4224$

Find the probability that in a day, there will be at least 1 birth.

This is:

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-13.4224}*13.4224^{0}}{(0)!} = 0.0000015$

Then

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0000015 = 0.9999985
$

0.9999985 = 99.99985% probability that in a day, there will be at least 1 birth.

7 0

3 years ago

Can someone help me fill out this chart

kotegsom [21]

Answer:

is there a y part of this equation?

Step-by-step explanation:

6 0

3 years ago

The 2 people that answer will get a brainliest.

photoshop1234 [79]

75 points 76 points 77 points 79 points 80 points 81 points 85 points 86 points 90 points 91 points

4 0

4 years ago

Read 2 more answers