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slavikrds [6]
2 years ago
11

Pls answer quick!! what is the area of the given polygon

Mathematics
1 answer:
Alla [95]2 years ago
6 0

Answer:

A = 124.71

Step-by-step explanation:

Please give me brainliest

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Write a quadratic function whose zeros are 2 and -12. 60 Point question Answer ASAP for brainliest!
ycow [4]

Answer:

x^2 + 10x - 24 = 0

Step-by-step explanation:

Two zeros are 2 and -12:

  1. x - 2 = 0
  2. x + 12 = 0

So the function is (x-2)(x+12) = 0

<=> x^2 + 12x - 2x - 24 = 0

<=> x^2 + 10x - 24 = 0

5 0
2 years ago
Find the measure of Arc JN<br><br><br>Find the measure of arcJN= <br><br><br>Find the m
Ede4ka [16]

Step-by-step explanation:

m(arc \: JN) = 360 \degree - (60 \degree + 150 \degree) \\  \hspace{57pt}= 360 \degree - 210 \degree \\  \hspace{57pt} =  150\degree \\  \\ m \angle K =  \frac{1}{2}  \times m(arc \: JN) \\   \hspace{30pt}= \frac{1}{2}  \times 150\degree  \\ \hspace{30pt} = 75\degree  \\

6 0
3 years ago
The slope that goes through the points (3,-4) and (-2,6)​
kicyunya [14]

Answer:

slope =  -2

Step-by-step explanation:

Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

         = \frac{6-[-4]}{-2-3}\\\\= \frac{6+4}{-2-3}\\\\= \frac{10}{-5}\\\\= -2

7 0
3 years ago
The slope of the line whose equation is 3y + 2x = 1 is: A.)-2/3 B.)-3/2 C.)1/3
mojhsa [17]

Answer:

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 3y + 2x = 1 into this form

Subtract 2x from both sides

3y = - 2x + 1 ( divide all terms by 3 )

y = - \frac{2}{3} x + \frac{1}{3} ← in slope- intercept form

with slope m = - \frac{2}{3} → A

4 0
3 years ago
Estimate the perimeter and area of the shaded figure to the nearest tenth.
Maru [420]

Answer:

Perimeter = 18.7 units

Area = 13.5 units²

Step-by-step explanation:

Perimeter of ADEC = AD + DE + EC + AC

Length of AD = 3 units

By applying Pythagoras theorem in ΔDBE,

DE² = DB² + BE²

DE² = 3² + 3²

DE = √18

DE = 4.24 units

Length of EC = 3 units

By applying Pythagoras theorem in ΔABC,

AC² = AB² + BC²

AC² = 6² + 6²

AC = √72

AC = 8.49 units

Perimeter of ADEC = 3 + 4.24 + 3 + 8.49

                                 = 18.73 units

                                 ≈ 18.7 units

Area of ADEC = Area of ΔABC - Area of ΔBDE

Area of ΔABC = \frac{1}{2}(AB)(BC)

                       = \frac{1}{2}(6)(6)

                       = 18 units²

Area of ΔBDE = \frac{1}{2}(BD)(BE)

                       = \frac{1}{2}(3)(3)

                       = 4.5 units²

Area of ADEC = 18 - 4.5

                        = 13.5 units²

6 0
3 years ago
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