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2 years ago

A circular pillar candle is 2.8 inches wide and 6 inches tall. What are the lateral area and surface area of the candle ?

Mathematics

1 answer:

Alexeev081 [22]2 years ago

4 0

Answer should be 36.95 if 1.4 is the radius

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If the diameter of a circle is 50 yards ,the radius is

Inessa05 [86]

Answer: 25 yards

Explanation:

Your radius is half the diameter

6 0

2 years ago

Read 2 more answers

Note: Enter your answer and show all the steps that you use to solve this problem Find the area. The figure is not drawn to scal

fgiga [73]

Answer:

area=13.8cm^2

Step-by-step explanation:

6 0

3 years ago

Y+x=1 show whether x and y show direct variation <br><br><br>plzz helpp

Thepotemich [5.8K]

Answer:

Step-by-step explanation:

Please write: "Determine whether y+x=1 shows direct variation."

No, it does not, because of the constant term, 1.

If we were to eliminate the 1 and write y + x = 0, then yes, this would represent direct variation.

7 0

2 years ago

Check my answer please?

Angelina_Jolie [31]

Hello,

In my old memories,
p(μ-2σ<=X<=μ+2σ)=95%
p(μ-3σ<=X<=μ+3σ)=99%

1000-2*200=1000-400=600
1000+2*200=1000+400=1400

Answer A

7 0

3 years ago

What are the ordered pairs of the

9966 [12]

Start by writing the system down, I will use $y$ to represent $f(x)$

$y=x^2-5x+3\wedge y=-3$

Substitute the fact that $y=-3$ into the first equation to get,

$-3=x^2-5x+3$

Simplify into a quadratic form ( $ax^2+bx+c=0$ ),

$x^2-5x+6=0$

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

$x^2+x(m+n)+mn=0$

which then must factor into

$(x+m)(x+n)=0$

And the solutions will be $m,n$ .

Clearly for small coefficients like ours $5,6$ , this is very easy to figure out. To get 5 and 6 we simply say that $m=3, n=2$ .

This fits the definition as $5=3+2$ and $6=2\cdot3$ .

So as mentioned, solutions will equal to $m=3, n=2$ but these are just x-values in the solution pairs of a form $(x,y)$ .

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are $(2,0)$ and $(3,0)$ .

Hope this helps :)

5 0

2 years ago