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Step2247 [10]
3 years ago
14

A circular pillar candle is 2.8 inches wide and 6 inches tall. What are the lateral area and surface area of the candle ?

Mathematics
1 answer:
Alexeev081 [22]3 years ago
4 0
Answer should be 36.95 if 1.4 is the radius
You might be interested in
[|(x-4)÷(x+5)|]\leq[4]
Katena32 [7]

Answer:

Solutions are;

x = -8

x = -3.2

Step-by-step explanation:

Here, we want to solve the given equation for x

|(x-4)/(x + 5)| = 4

From what we have, this is an absolute value equation and thus, we are going to have two solutions

These are;

x-4/x+ 5 = 4

x-4 = 4(x + 5)

x-4 = 4x + 20

x-4x = 20 + 4

-3x = 24

x = -24/3

x = -8

secondly;

x-4/x+5 = -4

x-4 = -4(x + 5)

x-4 = -4x - 20

x + 4x = -20 + 4

5x = -16

x = -16/5

x = -3.2

3 0
3 years ago
What is the value of x, the side length of the smallest square (please show work) Thanks!
Ratling [72]

Answer:

8 cm

Step-by-step explanation:

Ok lets on the biggest square we have 17 cm

17cm is the hypotenuse for the right triangle

The second largest's area is 225 cm^2

Sq root of 225 cm^2, is 15

To find x, lets plug the info we have to the pythagorean theorom

a^2 + b^2 = c^2\\a^2 + 15^2 = 17^2\\a^2 + 225 = 289\\\\289 - 225 = a^2\\64=a^2\\a = 8 cm

The side length of the smallest Square is 8 cm

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

7 0
3 years ago
The account
Orlov [11]

Answer:

850- 475= 375 increase over 2 months.

375 ÷2= $187.50

4 0
2 years ago
What is the area of this triangle?
Aleonysh [2.5K]
I think the area of this triangle is 27.1 square cm. Hope it help!
5 0
3 years ago
What is the length of the conjugate axis? (y-2)^2/16 -(x+1)^2/144=1
aleksandr82 [10.1K]

Answer: 24

A hyperbola is the locus of a point in a plane which moves in the plane in such a way that the ratio of its distance from a fixed point in the same plane to its distance from a fixed line is always constant, which is always greater than unity.

the fixed point is called the focus and the fixed line is directrix and the ratio is the eccentricity.

The general equation for the vertical hyperbola is

            [ (y-k)^2 / a^2 ] – [ (x-h)^2 / b^2 ] = 1

The conjugate axis of the vertical hyperbola is y = k

Length of the conjugate axis  = 2b

According to the question k = 2, h = -1, a = 4, b = 12

Length of the conjugate axis = 2b = 2 * 12  = 24

Learn more about hyperbola here :

brainly.com/question/3351710

#SPJ9

7 0
2 years ago
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