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Step2247 [10]
3 years ago
14

A circular pillar candle is 2.8 inches wide and 6 inches tall. What are the lateral area and surface area of the candle ?

Mathematics
1 answer:
Alexeev081 [22]3 years ago
4 0
Answer should be 36.95 if 1.4 is the radius
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Please help! See algebra question..
zhenek [66]

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this helps thank you

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8 0
3 years ago
Read 2 more answers
Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y
I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }

\mathbf{ YX = \sqrt{(3)^2+(6)^2} }

\mathbf{ YX = \sqrt{9+36} }

\mathbf{ YX = \sqrt{45} }

\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

8 0
3 years ago
Plzzzzz help …. T understand
bazaltina [42]
Pythagorean Theorem: a^2 + b^2 = c^2
a = 6
c = 9
b = ?
6^2 + b^2 = 9^2
36 + b^2 = 81
b^2 = 81 - 36
b^2 = 45
b = sqrt(45)
b = 6.71 miles
3 0
3 years ago
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