Question

Resiprocal of (-3/7)^2!​

Answer 1

Answer:

$\frac{49}{9}$

Step-by-step explanation:

Given

$(\frac{-3}{7})^{2!}$

Required

Determine the reciprocal

If a number is x, the reciprocal is: 1/x

So, the reciprocal of $(\frac{-3}{7})^{2!}$ is:

$\frac{1}{(\frac{-3}{7})^{2!}}$

$2! = 2*1 =2$

So, we have:

$\frac{1}{(\frac{-3}{7})^{2}}$

$\frac{1}{(\frac{-3^{2}}{7^{2}})}$

Evaluate all exponents

$\frac{1}{(\frac{9}{49})}$

Take inverse of 9/49

$\frac{49}{9}$

Hence, the reciprocal of $(\frac{-3}{7})^{2!}$ is $\frac{49}{9}$