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babymother [125]
3 years ago
14

Which of the following is true regarding the solutions to the logarithmic equation below? 2 log Subscript 3 Baseline (x) = 4. Lo

g Subscript 3 Baseline (x squared) = 4. X squared = 3 Superscript 4. X squared = 81. X = 9, negative 9 x = 9 and x = negative 9 are true solutions x = 9 and x = negative 9 are extraneous solutions x = 9 is an extraneous solution and x = negative 9 is a true solution x = 9 is a true solution and x = negative 9 is an extraneous solution.
Mathematics
1 answer:
Alisiya [41]3 years ago
6 0

Using logarithmic function concepts, it is found that the correct statement is:

x = 9 is a true solution and x = -9 is an extraneous solution.

<h3>What is a logarithmic function?</h3>

A logarithmic function is modeled by:

a = \log_{b}{x}

It means that:

b^a = x

In this problem, we have that:

2\log_{3}{x} = 4

Applying the power property:

\log_3{x^2} = 4

Applying the definition:

x^2 = 3^4

x^2 = 81

x = \pm 9

As the logarithm function is defined only for positive values, the correct statement is:

x = 9 is a true solution and x = -9 is an extraneous solution.

You can learn more about logarithmic function concepts at brainly.com/question/26302013

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-<br> Which table represents y as a function of x?<br> ~" M'L help
kow [346]

Answer:

G

Step-by-step explanation:

Each x value has its one y value.

This is what you need to have a function.

4 0
3 years ago
Exhibit 2-4A survey of 400 college seniors resulted in the following crosstabulation regarding their undergraduate major and whe
Misha Larkins [42]

Answer:

The percentage of college seniors with "Other" majors is 32%.

Step-by-step explanation:

The total number of college seniors surveyed is, <em>N</em> = 400.

The number of college seniors with "Other" majors is, <em>n</em> = 128.

The percentage of a value of <em>x</em> from <em>N</em> total is given as follows:

\text{Percentage of}\ x=\frac{x}{N}\times 100\%

Compute the percentage of college seniors with "Other" majors as follows:

\text{Others}\%=\frac{n}{N}\times 100\%

              =\frac{128}{400}\times 100\%\\\\=32\%

Thus, the percentage of college seniors with "Other" majors is 32%.

7 0
4 years ago
Read 2 more answers
1.) Any measure representing the center of a set of data arranged in a decreasing or increasing order of magnitude.
Marrrta [24]
  1. Answer: The median is defined the measure of the central value when arranged in ascending or descending order of magnitude.
  2. An average is a single number that represents the “middle” value of all the numbers in a list or set. There are three different types of average. These are called the mean, the median, and the mode.
  3. When the given data is arranged in ascending (or descending) order, then the middle most observation is the median of the data. Mean, median and mode are the representative values of a group of observations. They are also called the measures of central tendency of the data.
  4. If there are two numbers that appear most often (and the same number of times) then the data has two modes. This is called bimodal. If there are more than 2 then the data would be called multimodal. If all the numbers appear the same number of times, then the data set has no modes.
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3 0
3 years ago
PLEASE HELP
WINSTONCH [101]
A) Total cost of materials: 145.86 + 52.91 + 17.63 = $216.40
b) Percent cost of hardware: 17.63/216.40 = 0.081
c) Percent cost paint and hardware: (17.63 + 52.91)/216.40 = 0.326
8 0
4 years ago
What percent of 120 is 28.8
12345 [234]

Answer:

24

Step-by-step explanation:

Step 1: We make the assumption that 120 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$.

Step 3: From step 1, it follows that $100\%=120$.

Step 4: In the same vein, $x\%=28.8$.

Step 5: This gives us a pair of simple equations:

$100\%=120(1)$.

$x\%=28.8(2)$.

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have

$\frac{100\%}{x\%}=\frac{120}{28.8}$

7 0
3 years ago
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