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Leni [432]
2 years ago
10

Two friends live 3 miles apart along the same road. If they walk toward each other at rates that differ by half mile per hour an

d meet 24 minutes later, how fast is each person walking
Mathematics
1 answer:
Slav-nsk [51]2 years ago
8 0

Answer: their speeds are 3.5mph and 4 mph

Step-by-step explanation:

Since both friends live 3 miles apart along the same road, by the time they meet, they would have covered 3 miles.

Let x represent the speed of the slower friend.

If differ by half mile per hour, it means that the speed of the faster friend is (x + 0.5) mph

They meet after 24 minutes(24/60 = 0.4 hours)

Distance = speed × time

Distance covered by the slower friend in 0.4 hours is

x × 0.4 = 0.4x

Distance covered by the faster friend in 0.4 hours is

0.4(x + 0.5) = 0.4x + 0.2

Since the total distance is 3 miles, then

0.4x + 0.4x + 0.2 = 3

0.8x = 3 - 0.2 = 2.8

x = 2.8/0.8

x = 3.5 mph

The speed of the faster friend is

3.5 + 0.5 = 4 mph

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The probability that aperson living in a certaincity owns a dog is estimated to be 0.3. Find the probabilitythat the tenth perso
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Given,

Consider the interview of a person is a trial.

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P(X =x ) = b(x: k, p) = [(x-1)(k-1)] p^kq^r^-^k

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Now, Lets find the probability that the tenth person randomly interviewed in that city is the fifth one to own a dog

Using equation (1), we get:

P(X = 10) = b(10: 5, 0.3)

                = [(10-1) (5 - 1)](0.3)^5(0.7)^1^0^-^5

               = [(9)(4)] (0.3)^5(0.7)^1^0^-^5

               = 0.05146

Hence, The probability that the tenth person randomly interviewed in that city is the fifth one to own a dog = 0.051

Learn more about Probability at:

brainly.com/question/743546

#SPJ9                                  

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