Answer:
it's the first one
Step-by-step explanation:
since all of them go up to 8 on the graph it
the graph represents it going down since the first one is the only one to go down that one represents the graph precisely.
Since the triangles are similar, then 32 = x+7 those two angles are too
solve for "x"
now using proportions

solve for JK

solve for KG
the scale factor of the perimeter of both triangles is just the same as the ratio of the sides, or
The foci need to be equal distances from the center of the eclipse.
See the attached picture. I marked off all the points that were given as choice and from this you can see that that (-5,-4) and (-5,2) are both 3 units away from the center.
The answer is: (-5,-4) and (-5,2)
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➷ As there would be 2 circles, you'd need to find the area of a circle and then multiply it by 2
To start with, we can use this:
2 (
r^2)
^^ This represents the surface area of the two circles
A cylinder also has a rectangle which is rolled to form the shape
As we know, the formula of a rectangles area is length x width
The width of the rectangle would be equal to the circumference of a circle
circumference of circle = 
The length of the rectangle would be the height of the cylinder
We can use this:

This would calculate the surface area as it would find the area of the rectangle plus the area of the two circles.
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An equation is formed of two equal expressions. The solution is (-9,-2).
<h3>What is an equation?</h3>
An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
Given the equation x + 3y = -15 and -3x + 2y = 23,
Step 1- Multiply the equations to make the coefficients match in either the x- or y-variable.
x + 3y = -15
3x + 9y = -45
Step2- After you multiply, add or subtract the two equations.
3x + 9y -3x + 2y = -45 + 23
Step 3- Then solve for the variables that is left.
11y = -22
y = -2
Step4- Substitute the value of y in any one of equations to solve for x.
x + 3(-2) = -15
x - 6 = -15
x = -9
Hence, The solution is (-9,-2).
Learn more about Equation:
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