How to find these key features to sketch a rough graph

Can someone help me please??

vodka [1.7K]

Answer:

11,4 > 11 > 9,8 > 1

Step-by-step explanation:

To list the numbers from smallest to largest we need to determine the value of them in same/similar format

11 and 1 is in same format

The approximate value of $\pi ^{2}$ 9.8

the root of $\sqrt{121}$ = 11

the root of $\sqrt{130}$ is = 11.4 approximately

Now we have them as real numbers we can evaluate

11,4 > 11 > 9,8 > 1 we don't need to write 11 twice but if needed we can write is as:

11,4 > 11 = 11 > 9,8 > 1

3 0

3 years ago

Please simplify this expression

ale4655 [162]

It’s 4R+7

:)))))))))))))))))))

6 0

3 years ago

A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

What is the area of the green triangle? A) 23 cm2 B) 30 cm2 C) 46 cm2 D) 65 cm2

shusha [124]

You have to calculate the air, a=h*b/2 so the answer is d)

5 0

3 years ago

Read 2 more answers

25 10. Fill in the blanks. a. 7+9_9+7 c. 16x12= x 16

Yakvenalex [24]

Answer:

=

192

Step-by-step explanation:

idek what the last question is asking

5 0

3 years ago