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NikAS [45]
3 years ago
5

If h(x) = 5x - 3 and j(x) = -2x, solve hlj(2)] and select the correct answer below. (1 point)

Mathematics
1 answer:
BARSIC [14]3 years ago
4 0

Answer:

-23

Step-by-step explanation:

We are given the functions;

h(x) = 5x - 3 and j(x) = -2x

Now, we want to find h[j(2)]

j(2) = -2(2)

j(2) = -4

Thus;

h(-4) = 5(-4) - 3

h(-4) = -20 - 3

h(-4) = - 23

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Would appreciate some help with this:<br><br> Verify (sinq+cosq)^2 - 1 = sin2q
Phantasy [73]

Hello from MrBillDoesMath!

Answer:

See Discussion below

Discussion:

(sinq + cosq)^2 =                                     => (a +b)^2 = a^2 + 2ab + b^2

(sinq)^2 + (cosq)^2 + 2 sinq* cosq        => as (sinx)^2 + (cosx)^2 = 1

1 + 2 sinq*cosq              (*)


Setting a = b = q in the trig identity:

sin(a+b) = sina*cosb + cosa*sinb                      

sin(2q) =                      (**)

sinq*cosq + cosq*sinq      => as both terms are identical

2 sinq*cosq


Combining (*) and (**)

(sinq + cosq)^2 = 1 + 2sinq*cosq     => (**) 2sinq*cosq =  sqin(2q)

                          = 1 +  sin(2q)

Hence

(sinq + cosq)^2  = 1 +  sin(2q)            => subtracting 1 from both sides

(sinq + cosq)^2  - 1 =   sin(2q)  

The last statement is what we are trying to prove.



Thank you,

MrB

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