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Karo-lina-s [1.5K]

2 years ago

5

I need help, please anyone!

1 answer:

Olegator [25]2 years ago

7 0

1.45 is the answer! brainliest

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Ms. Ache is paid $1250 per week but it's fined $100 each day she is late to work Ms.A che wants to make at least $3,000 over the

nordsb [41]

She can be late 7 days max

6 0

2 years ago

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WILL GIVE BRAINLIEST Raul, Chris, and Jerry together sold 88 tickets for the school banquet. Raul sold 30 tickets, and Chris sol

zloy xaker [14]

Answer:

20 or B)

Step-by-step explanation:

88-30= 58

58-38= 20

Jerry sold 20

Hope this helped.

A brainliest is always appreciated.

8 0

1 year ago

Noam chose 3 songs from a pile of 20 songs to play at a piano recital. What is the probability that she chose The Entertainer, S

OverLord2011 [107]

Answer:

3/20

Step-by-step explanation:

She chose 3 songs out of twenty so those three songs should be out of that twenty.

7 0

2 years ago

Save me the headache

maxonik [38]

$(9\sin2x+9\cos2x)^2=81$

Taking the square root of both sides gives two possible cases,

$9\sin2x+9\cos2x=9\implies\sin2x+\cos2x=1$

or

$9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1$

Recall that

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

If $\alpha=2x$ and $\beta=\dfrac\pi4$ , we have

$\sin\left(2x+\dfrac\pi4\right)=\dfrac{\sin2x+\cos2x}{\sqrt2}$

so in the equations above, we can write

$\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1$

Then in the first case,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=\dfrac\pi4+2n\pi\text{ or }\dfrac{3\pi}4+2n\pi$

(where $n$ is any integer)

$\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi$

$\implies x=n\pi\text{ or }\dfrac\pi4+n\pi$

and in the second,

$\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}$

$\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi$

$\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi$

$\implies x=-\dfrac\pi4+n\pi\text{ or }-\dfrac\pi2+n\pi$

Then the solutions that fall in the interval $[0,2\pi)$ are

$x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4$

5 0

2 years ago

Read 2 more answers

Find x: a - bx = cx + d

V125BC [204]

Answer:

x= -(d-a)/(b+c)

Step-by-step explanation:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero

5 0

2 years ago