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Ann [662]
3 years ago
11

Y=5(x/10-2) solve for x ​

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
7 0
Y=x/2-2 -> y+10=x/2 -> x=2(y+10)
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Jamie has 7/10 of a pound of chicken to cook for dinner if she's going to put the chicken in between three people how much chick
AURORKA [14]

Answer:

Each person will get \frac{7}{30} or approximately 0.23 pounds of chicken.

Step-by-step explanation:

This is a word problem involving fractions.  Using key words and phrases from the problem, we can decide which operation we need to use to solve.  Since Jamie is splitting the chicken equally between three people, she would need to divide the amount of chicken she has by 3:

\frac{7}{10}÷\frac{3}{1}

Since we can't divide fractions, we need to use the 'keep-change-flip' rule to keep the first fraction, change the operation to multiplication and flip the second fraction:

\frac{7}{10}*\frac{1}{3}=\frac{7}{30}

We can convert the fraction into a decimal by dividing the numerator by the denominator:  7÷30≈0.23 pounds per person.

5 0
4 years ago
at Phil's work there are 12 part time workers and 18 full time workers what is the ratio of part time workers to total workers​
BabaBlast [244]

Answer:

the ratio of part time workers to total workers are 12/30

3 0
3 years ago
How do you solve for y?
ss7ja [257]
I’m pretty sure you just solve exactly like that
-7(-2)-1 =13 at least I’m told that \_( •-• )_/
4 0
3 years ago
What is the rate in feet per second? 10 feet 16 seconds
Ierofanga [76]
Feet
_____
second


10 feet
________
16 second

equals

.625 feet per second
7 0
3 years ago
Sam entered three functions into a graphing calculator, y1 = x + 2, y2 = x2 + 2, and y3 = 2x. A portion of the table created by
V125BC [204]
For this case we have the following functions:
 y1 = x + 2

y2 = x ^ 2 + 2

y3 = 2 ^ x
 
 When x = 0 we have:
 For y1:
 y1 = 0 + 2

y1 = 2
 For y2:
 y2 = 0 ^ 2 + 2

y2 = 0 + 2

y2 = 2
 Therefore, we have to:
 y1 = y2


 When x = 5 we have:
 For y2:
 y2 = 5 ^ 2 + 2

y2 = 25 + 2

y2 = 27
 For y3:
 y3 = 2 ^ 5

y3 = 32
 Therefore, we have to:
 y2 \ \textless \ y3


 When x = -1 we have:
 For y1:
 y1 = -1 + 2

y1 = 1
 For y2:
 y2 = (-1) ^ 2 + 2

y2 = 1 + 2

y2 = 3

 For y3:
 y3 = 2 ^ {-1}

y3 = 1/2

y3 = 0.5
 Therefore, we have to:
 y3 \ \textless \ y1 \ \textless \ y2


 Answer:
 
When x = 0, y1 = y2
 
When x = 5, y2 <y3
 
When x = -1, y3 <y1 <y2
4 0
4 years ago
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