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2 years ago

Is the following function even, odd, or neither f(x)=x^3/x+1

Mathematics

1 answer:

algol [13]2 years ago

8 0

Answer: Odd

Step-by-step explanation:

Odd functions are functions where the exponent of the leading term is odd. In this case, the exponent of 3 is odd, so the function is odd.

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The law of exponent used in is _____

Lady bird [3.3K]

A is the answer I just did that on my usa test prep

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3 years ago

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Daniela facing a 12 ft tall statue that is 15 ft away. She can see the reflection of the top of the statue in a puddle on the gr

mote1985 [20]

Answer:

36 ft

Step-by-step explanation:

Daniela facing a 12 ft tall statue that is 15 ft away. She can see the reflection of the top of the statue in a puddle on the ground 5 ft in front of her. How tall is Daniela?

Hence, this is calculated as:

5ft/15ft = 12 ft/Daniela's height

Cross Multiply

5ft × Daniela's height = 15ft × 12ft

Daniela's height = 15ft × 12 ft/5ft

= 36ft

Therefore, Daniela's height = 36 ft

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3 years ago

The question is in the picture

Lera25 [3.4K]

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3 years ago

Hi hottie, pls help me !

yulyashka [42]

Answer:

1200

0.65

The answers are in the function

6 0

3 years ago

Can someone solve this?

ladessa [460]

First question:

Recall that $\cos^2x+\sin^2x=1$ and $\sqrt{x^2}=|x|$ for all $x$ . So

$\sqrt{1-\cos^2x}=\sqrt{\sin^2x}=|\sin x|$

$\sqrt{1-\sin^2x}=\sqrt{\cos^2x}=|\cos x|$

For $0$ , we expect both $\cos x>0$ and $\sin x>0$ (i.e. the sine and cosine of any angle that lies in the first quadrant must be positive). By definition of absolute value, $|x|=x$ if $x>0$ .

So we have

$\dfrac{\sqrt{1-\cos^2x}}{\sin x}+\dfrac{\sqrt{1-\sin^2x}}{\cos x}=\dfrac{\sin x}{\sin x}+\dfrac{\cos x}{\cos x}=1+1=\boxed{2}$

making H the answer.

Second question:

C is always true, because the inequality reduces to x > y.

6 0

4 years ago