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ss7ja [257]
2 years ago
14

Pleases help it’s due soon

Mathematics
1 answer:
Hunter-Best [27]2 years ago
7 0

Answer:

8x+85

Step-by-step explanation:

you add that to this to that theres your answer

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MAAATTTHH HELP PLEEASSEE WILL GIVE 5 STARS FOR CORRECT ANSWERS
Cloud [144]
I know you don't wanna do the work or don't know how but just get the m a t h w a y a-p-p and type the equations in and it'll tell you what x is
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3 years ago
C. Gage bought a new car for $29,000 to use while he is away at college. The car depreciates (decreases in value) by 11% annuall
OverLord2011 [107]

Answer:

a. The value of the car will be $18,195.25

b. (i) 2.5 hours

(ii) 25 problems each

Step-by-step explanation:

a. To calculate the value of the car after four years, what we shall use is the exponential formula below;

F = PV( 1 - r)^t

where F is the value at year 4

PV is the present price = $29,000

r is the rate = 11% = 11/100 = 0.11

t is the time = 4 years

Substituting these values, we have;

F = 29,000(1-0.11)^4 = 29000(0.89)^4 = $18,195.25

The value of the car when he graduates will be $18,195

b. Let the number of hours it will take for both to have written the same number if problems

be x

For Ms B, the number of problems she would have written at that time will be 10 + 6(x)

For Ms D , the number of problems will be 10 * x = 10x

To get the time it will take for both to write same number of problems, we will need to equate the number of problems they would have written by hour x

Hence;

10 + 6x = 10x

10x-6x = 10

4x = 10

x = 10/4 = 2.5 hours

The number of problems would be;

For Ms B = 6(2.5) + 10 = 15 + 10 = 25

For Ms D = 10(2.5) = 25

They both would have written 25 problems at that time

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3 years ago
- The ordered pairs (0,0), (2, 4), (4,8), and (6, 12) represent a function. What is the rule for this
mr_godi [17]
The answer for this problem is y=2X
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Hi, can you help to find (all the roots/zeros), please!!!
OLga [1]

Solution

Given the quadratic equation

x^2-2x-38=0

we need to find the zeros of the equation

To do that, we use the completing the square method

Step 1. Add 38 to both sides

\begin{gathered} \Rightarrow x^2-2x-38+38=38 \\  \\ \Rightarrow x^2-2x=38 \end{gathered}

Step 2: add the square of half of the coefficient of x to both sides

That is;

\begin{gathered} \Rightarrow x^2-2x+(\frac{1}{2}\cdot(-2))^2=38+(\frac{1}{2}\cdot(-2))^2 \\  \\ \Rightarrow x^2-2x+1=38+1 \\  \\ \Rightarrow x^2-2x+1=39 \\  \\ \Rightarrow(x-1)^2=39 \end{gathered}

Step 3: Simplify the above expression;

\begin{gathered} \Rightarrow x-1=\pm\sqrt[]{39} \\  \\ \Rightarrow x=1\pm\sqrt[]{39} \end{gathered}

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PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS
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Here is the answer sis lol

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