The applicable identity is ...
... cos(a)cos(b) = (1/2)(cos(a+b) +cos(a-b))
Let a=36t, b=6t and substitute this into your expression. Then you have ...
... 20cos(36t)cos(6t) = 20·(1/2)(cos(36t+6t) + cos(36t-6t))
... = 10(cos(42t) + cos(30t))
... = 10cos(42t) +10cos(30t)
Answer:
Please check explanations for answer to the question
Step-by-step explanation:
The exponential relation can generally be represented as ;
y = I (1 + x)^n
where I is the initial value
1 + x represents the growth rate
n represents the time such as number of years
y represents the value after n count
a) The value 1200 represents the initial count of bacteria in the study
b) 1.8 represents the growth rate of the bacteria population in the culture
c) 1000 represents the initial bacteria population in the second function
The difference mean that the initial population in the first case study is greater than what we have in the second function
Answer:
240^2 - 120x
Step-by-step explanation:
4(2x - 1) x 3 x (2x 5)
4(2x - 1) x 3 x (10x)
4(2x - 1) x 3 x 10x
120x x (2x-1)
240^2 - 120x
<h3>
Answer: D) 7</h3>
===================================================
Explanation:
a31 means "the value in the third row, first column". That value is 7
As another example, a22 = 3 since 3 is in the second row, second column.
Another example: a12 = -1 because we're in the first row and second column.
This is a 3x2 matrix due to it having 3 rows and 2 columns.
Question:
Complete question for this is to find the equation for this and may be the graph.
Explanation:
As for the oscillation motion, initially peak is occurring hence it will be a cosine function with peak value of 3(cm).
To calculate time period, the whole cycle should be 360°
i.e.
cos (Xπ.t) = cos (360)
as the cycle completes at 1.2 sec hence by putting t=1.2, answer should be 360.
i.e.
X*180*t=360
X*180*1.2=360
X=5/3
So, the required equation is
Graph for this equation is attached here with this answer.
In graph,
x-axis: t=0 ~ t=1.2
y-axis: f(x)=-4 ~ f(x)=4
