Question

4)_Slope = 4; contains (-5, - 13) I need help please

Answer 1

Answer:

The equation of the line with slope = 4 and point (-5, -13)

will be:

• $y=4x+7$

Step-by-step explanation:

Given

• slope = m = 4

• point = (-5, -13)

As the point-slope form of the equation of line is

$y-y_1=m\left(x-x_1\right)$

where m is the slope.

substituting the values m = 4 and the point (-5, -13)

$y-y_1=m\left(x-x_1\right)$

$y-\left(-13\right)=4\left(x-\left(-5\right)\right)$

$y+13=4\left(x+5\right)$

subtract 13 from both sides

$y+13-13=4\left(x+5\right)-13$

$y=4x+7$

Therefore, the equation of the line with slope = 4 and point (-5, -13)

will be:

$y=4x+7$