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Nana76 [90]
3 years ago
7

15% of R560 - 15% of R500 is:​

Mathematics
1 answer:
Dahasolnce [82]3 years ago
8 0

15% of R560 - 15% of R500

=> 0.15 × 560 – 0.15 × 500

=> 0.15 ( 560–500)

=> 0.15 × 60

=> Rs. 9

HOPE IT HELPS

PLEASE MARK ME BRAINLIEST ☺️

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Please answer ASAP!
7nadin3 [17]

Answer:

h = 4.5 inches

Step-by-step explanation:

The area of a trapezoid is given by

A = 1/2 (b1+b2) h

We know A b1 and b2

20.25 = 1/2 (5+4)*h

20.25 = 9/2 h

Multiply each side by 2/9 to isolate h

2/9 * 20.25 = 2/9 *9/2 h

4.5 =h

6 0
3 years ago
What is the sum of the arithmetic sequence 151, 137, 123,..if there are 26 terms?
ElenaW [278]
First term: a1 = 151
common difference: d = -14 (we decrease by 14 each time, eg, 151-14 = 137)

nth term of this arithmetic sequence is...
an = a1+d(n-1)
an = 151+(-14)(n-1)
an = 151-14n+14
an = -14n+165

This will be used in the formula below

Sn = n*(a1+an)/2
<span>Sn = n*(151+(-14n+165))/2
</span><span>S26 = 26*(151+(-14*26+165))/2 ... replace every n with 26
</span>S26 = -624

The final answer here is choice C) -624
<span>
</span>
5 0
3 years ago
four students have to give a speech in class today. In how many different orders can they give their speeches?
bulgar [2K]

Answer:

There are 24 possible outcomes.

Step-by-step explanation:

1. 1-2-3-4

2. 1-4-3-2

3. 1-4-2-3

4. 1-2-4-3

5. 1-3-2-4

6. 1-4-3-2

7. 2-4-3-1

8. 2-1-3-4

9. 2-1-4-3

10. 2-4-1-3

11. 2-3-1-4

12. 2-3-4-1

13. 3-2-1-4

14. 3-2-4-1

15. 3-1-2-4

16. 3-1-4-2

17. 3-4-1-2

18. 3-4-2-1

19. 4-3-2-1

20. 4-3-1-2

21. 4-2-3-1

22. 4-2-1-3

23. 4-1-2-3

24. 4-1-3-2

Hope this helps!!


5 0
3 years ago
Write a percent that has a value between the two decimals 0.4 and 0.5
Juliette [100K]
A percent would be 0.45 
5 0
3 years ago
Jason wants to plant 66 carrot seeds and 44 onion bulbs. He would like to plant them so
dexar [7]

The greatest number of plants he can have in each row is 22

He would have 3 rows of carrots

He would have 2 rows of onions

<h3>Greatest Common Factor</h3>

From the question, we are to determine the greatest number of plants he can have in each row

From the given information,

Jason wants to plant 66 carrot seeds and 44 onion bulbs

The greatest number of plants he can have in each row is the greatest common factor of 66 and 44

Factors of 66: 1, 2, 3, 6, 11, 22, 33, and 66

Factors of 44:  1, 2, 4, 11, 22 and 44

The greatest common factor of 66 and 44 is 22

Thus,

The greatest number of plants he can have in each row is 22

He would have 66/22 rows of carrots

66/22 = 3

Thus,

He would have 3 rows of carrots

He would have 44/22 rows of onions

44/22 = 2

Hence, he would have 2 rows of onions

Learn more on Greatest Common Factors here: brainly.com/question/5535901

#SPJ1

3 0
2 years ago
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