Question

There are 3 types of sweets in a jar.

Answer 1

Answer:

$\frac{2}{3}$

Step-by-step explanation:

Given:

Number of eclairs = 3

Number of humbugs = $2x + 6=2(x+3)$

Number of mints = $x$

Therefore, total number of sweets in the jar is,

$S=3+2x+6+x=3x+9=3(x+3)$

Now, probability of selecting a sweet to be humbug is given as:

$P(humbug)=\frac{\textrm{number of humbugs}}{\textrm{number of sweets}}\\P(humbug)=\frac{2(x+3)}{3(x+3)}=\frac{2}{3}$

Therefore, the probability that it is a humbug is $\frac{2}{3}$.