All categories

3 years ago

Plz use the graph help asap show work

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

7 0

Question 9.)
5-2(5)-1
10-1
Y=9
(X,Y) = 5,9
2- 2(2)-1
4-1
Y=3
(X,Y)= 2,3
0- 2(0)-1
2-1
Y=1
(X,Y)= 0,1
10)
4- 3(4)-7
12-7
Y=5
(X,Y)=4,3
1- 3(1)-7
3-7
Y=-4
(X,Y)= 1,-4
0- 3(0)-7
0-7
Y=-7
(X,Y)= 0,-7
(I believe you are supposed to plot the (X,Y) points on the graph)

You might be interested in

I need help with this

defon

i guess just times them all then divide up by how many numbers you have

3 0

3 years ago

What is n?<br> The answer format is <br> n=

vladimir1956 [14]

I hope this helps. If you don’t understand it I will explain it again

5 0

3 years ago

Need help with this

den301095 [7]

n = 66

Step-by-step explanation:

you can make a proportion 3/99 = 2/x

$\frac{3}{99} = \frac{2}{x}$

99 * 2= 198

3 * x = 3x

so the equation would be 198 = 3x

than do 198 ÷ 3 on ur calculator

so x (or n in this context) would equal 66

7 0

2 years ago

The school system is trying to help their students be more successful. They are going to hire tutors to help. They must have mor

dexar [7]

Answer:

a. $x-y > 0$

b. $x+y \leq 50$

c. x=26; y=24 or (24,26)

Step-by-step explanation:

Let x = number of teachers hired.

Let y = number of tutors hired.

Now solving for part a we get

a. Write an inequality that represents the statement that the number of teachers hired must exceed the number of tutors hired.

$x-y > 0$

solving for part b we get;

b. Write an inequality that represents the statement that the maximum number of teachers and tutors is 50.

$x+y \leq 50$

solving for part c we get;

c. Choose a point that satisfies the situation, and explain why you chose that number of tutors and teachers.

Now we know that $x-y > 0$ also $x+y \leq 50$

x=26; y=24

(24,26)

Explanation: To make number of teacher more than number of tutors this is the maximum value we can achieve for the requirement.

6 0

3 years ago

Determine if this equation is either true or false: y^13/(y^3)^4 = y^8 * y^−9

Marrrta [24]

The equation is true.
y^13/y^12 = y^8 * y^-9
y=y^8 * y^-9
y=y^-1
y=1/y
y-1/y=0
y
y^2 - 1 = 0
y = 1 , -1

5 0

2 years ago