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telo118 [61]
3 years ago
8

Please help with these if you can

Mathematics
2 answers:
Mila [183]3 years ago
7 0

Answer:

the photo is blurry

Step-by-step explanation:


MrRissso [65]3 years ago
3 0

The image is quite unclear...

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Solving a right triangle means using given information to find all the angles and side lengths on
nikklg [1K]
All triangles add up to 180 degrees so I don’t get the just of the question but there you go.
4 0
4 years ago
Lauren is going to invest in an account paying an interest rate of 3.4%
zzz [600]

Answer:

45

Step-by-step explanation:

7 0
3 years ago
Anna walks at a constant rate of 8 miles every 2 hours Graph a line to show the relationship between the time in hours, 1 and th
stiks02 [169]

Answer:

We see that the only complete time-distance pair indicates that she walked 6.4 miles in 2 hours. If she walked at a constant speed, we can conclude that girl walked 3.2 miles in 1 hour. Using this speed, we can find the remaining values in the table. The easier entry to complete is finding out how far she walked in 5 hours: 5 hours⋅3.2 miles/hour=16 miles. To find out how long it took to walk 8 hours we can either notice that 8 is half of 16, so it took half the time to walk half the distance or we can divide 8 miles by 3.2 miles per hour to find that it took 2.5 hours

Step-by-step explanation:

8 0
3 years ago
Casey went to the store and purchased 12 pairs of socks, and 3 pairs of shoes for $18.20 each. She spent a total of $81.60. How
8_murik_8 [283]
$2.25/ per pair of socks

3x18.20 = 54.6
81.6 - 54.6 = 27
27/12 = 2.25
Answer 2.25
3 0
3 years ago
Find the exact value of the trigonometric expression given that sin(u) = -(3/5),
GuDViN [60]

Recall that

\cot(u+v)=\dfrac{\cos(u+v)}{\sin(u+v)}=\dfrac{\cos u\cos v-\sin u\sin v}{\sin u\cos v+\cos u\sin v}=\dfrac{\cot u\cot v-1}{\cot v+\cot u}

Also, recall that for all \theta,

\cos^2\theta+\sin^2\theta=1

With \frac{3\pi}2, we can expect \cos u>0, and with 0, \sin v>0. So from the above identity it follows that

\cos u=\sqrt{1-\sin^2u}=\dfrac45\implies\cot u=\dfrac{\cos u}{\sin u}=-\dfrac43

and

\sin v=\sqrt{1-\cos^2v}=\dfrac8{17}\implies\cot v=\dfrac{\cos v}{\sin v}=\dfrac{15}8

and so

\cot(u+v)=\dfrac{-\frac43\frac{15}8-1}{\frac{15}8-\frac43}=\boxed{-\dfrac{84}{13}}

6 0
3 years ago
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