Answer:
look at the picture I sent
Answer:
(A) 
(b) 
(c) 
(d) 
Step-by-step explanation:
We have given expression and we have to simplify the expression using exponent property
(A) 
So 
(b) 
So 
(c) 
So 
(d) 
Rewriting the left-hand side as follows,

Step-by-step explanation:
There are a total of 4 + 1 + 9 + 6 = 20 cookies. So the probabilities of each type for a random cookie are:
P(oatmeal raisin) = 4/20 = 1/5
P(sugar) = 1/20
P(chocolate chip) = 9/20
P(peanut butter) = 6/20 = 3/10
The answer is correct but i do not know what ARLENE did wrong