What is the equation of the line passing through the points (2/5, 19/20) and (1/3, 11/12) in slope-intercept form?

'What is the surface area, in square inches, of an 8-inch

scoray [572]

Surface are is length times height.
8*8=64
a cube has 6 sides
64*6=384

8 0

3 years ago

Please help! -300 120 300

oksano4ka [1.4K]

Answer:

120

Step-by-step explanation:

6 0

3 years ago

Find all the missing sides or angles in each right triangles

astra-53 [7]

In previous lessons, we used the parallel postulate to learn new theorems that enabled us to solve a variety of problems about parallel lines:

Parallel Postulate: Given: line l and a point P not on l. There is exactly one line through P that is parallel to l.

In this lesson we extend these results to learn about special line segments within triangles. For example, the following triangle contains such a configuration:

Triangle △XYZ is cut by AB¯¯¯¯¯¯¯¯ where A and B are midpoints of sides XZ¯¯¯¯¯¯¯¯ and YZ¯¯¯¯¯¯¯ respectively. AB¯¯¯¯¯¯¯¯ is called a midsegment of △XYZ. Note that △XYZ has other midsegments in addition to AB¯¯¯¯¯¯¯¯. Can you see where they are in the figure above?

If we construct the midpoint of side XY¯¯¯¯¯¯¯¯ at point C and construct CA¯¯¯¯¯¯¯¯ and CB¯¯¯¯¯¯¯¯ respectively, we have the following figure and see that segments CA¯¯¯¯¯¯¯¯ and CB¯¯¯¯¯¯¯¯ are midsegments of △XYZ.

In this lesson we will investigate properties of these segments and solve a variety of problems.

Properties of midsegments within triangles

We start with a theorem that we will use to solve problems that involve midsegments of triangles.

Midsegment Theorem: The segment that joins the midpoints of a pair of sides of a triangle is:

parallel to the third side. half as long as the third side.

Proof of 1. We need to show that a midsegment is parallel to the third side. We will do this using the Parallel Postulate.

Consider the following triangle △XYZ. Construct the midpoint A of side XZ¯¯¯¯¯¯¯¯.

By the Parallel Postulate, there is exactly one line though A that is parallel to side XY¯¯¯¯¯¯¯¯. Let’s say that it intersects side YZ¯¯¯¯¯¯¯ at point B. We will show that B must be the midpoint of XY¯¯¯¯¯¯¯¯ and then we can conclude that AB¯¯¯¯¯¯¯¯ is a midsegment of the triangle and is parallel to XY¯¯¯¯¯¯¯¯.

We must show that the line through A and parallel to side XY¯¯¯¯¯¯¯¯ will intersect side YZ¯¯¯¯¯¯¯ at its midpoint. If a parallel line cuts off congruent segments on one transversal, then it cuts off congruent segments on every transversal. This ensures that point B is the midpoint of side YZ¯¯¯¯¯¯¯.

Since XA¯¯¯¯¯¯¯¯≅AZ¯¯¯¯¯¯¯, we have BZ¯¯¯¯¯¯¯≅BY¯¯¯¯¯¯¯¯. Hence, by the definition of midpoint, point B is the midpoint of side YZ¯¯¯¯¯¯¯. AB¯¯¯¯¯¯¯¯ is a midsegment of the triangle and is also parallel to XY¯¯¯¯¯¯¯¯.

Proof of 2. We must show that AB=12XY.

In △XYZ, construct the midpoint of side XY¯¯¯¯¯¯¯¯ at point C and midsegments CA¯¯¯¯¯¯¯¯ and CB¯¯¯¯¯¯¯¯ as follows:

First note that CB¯¯¯¯¯¯¯¯∥XZ¯¯¯¯¯¯¯¯ by part one of the theorem. Since CB¯¯¯¯¯¯¯¯∥XZ¯¯¯¯¯¯¯¯ and AB¯¯¯¯¯¯¯¯∥XY¯¯¯¯¯¯¯¯, then ∠XAC≅∠BCA and ∠CAB≅∠ACX since alternate interior angles are congruent. In addition, AC¯¯¯¯¯¯¯¯≅CA¯¯¯¯¯¯¯¯.

Hence, △AXC≅△CBA by The ASA Congruence Postulate. AB¯¯¯¯¯¯¯¯≅XC¯¯¯¯¯¯¯¯ since corresponding parts of congruent triangles are congruent. Since C is the midpoint of XY¯¯¯¯¯¯¯¯, we have XC=CY and XY=XC+CY=XC+XC=2AB by segment addition and substitution.

So, 2AB=XY and AB=12XY. ⧫

Example 1

Use the Midsegment Theorem to solve for the lengths of the midsegments given in the following figure.

M, N and O are midpoints of the sides of the triangle with lengths as indicated. Use the Midsegment Theorem to find

A. MN. B. The perimeter of the triangle △XYZ. A. Since O is a midpoint, we have XO=5 and XY=10. By the theorem, we must have MN=5. B. By the Midsegment Theorem, OM=3 implies that ZY=6; similarly, XZ=8, and XY=10. Hence, the perimeter is 6+8+10=24.

We can also examine triangles where one or more of the sides are unknown.

Example 2

Use the Midsegment Theorem to find the value of x in the following triangle having lengths as indicated and midsegment XY¯¯¯¯¯¯¯¯.

By the Midsegment Theorem we have 2x−6=12(18). Solving for x, we have x=152.

Lesson Summary

8 0

3 years ago

Jack picked 76 apples. Of these, he sold 4y apples to Juanita and 3t apples to Sylvia. If he kept the remaining apples, how many

Alex Ar [27]

Answer:

Number of apples remaining with him will be 2 when we combined both the conditions.

Step-by-step explanation:

Given;

Number of apples Jack Picked =76

Number of apples sold to Juanita = 4y

Number of apples sold to Sylvia = 3t

We need to find the Number of apples remaining with him.

Solution:

To find the Number of apples remaining with him we will Subtract Number of apples sold to Juanita and Number of apples sold to Sylvia from Number of apples Jack Picked.

framing in equation form we get;

Number of apples remaining with him = $76-4y-3t$

Now Given:

Condition 1 : y ≥ 15 and t = 2

So we can assume y =16 and t =2

Number of apples remaining with him = $76-4\times16-3\times2 = 76 -64 -6 = 6$

Also we can say that y =17 and t =2

Number of apples remaining with him = $76-4\times17-3\times2 = 76 -68 -6 = 2$

So the Given data is Insufficient to find the Number of apples remaining with him.

Condition 2 : y = 17

Number of apples remaining with him = $76-4\times17-3t = 76 -68 -3t = 8-3t$

Since value of t is not given we can say that;

Given data is insufficient to find the number of apples remaining with him.

Condition 3 : Combined i.e y = 17 and y≥ 15 t = 2

Number of apples remaining with him = $76-4\times17-3\times2 = 76 -68 -6 = 2$

Hence we can say that Number of apples remaining with him will be 2 when we combined both the conditions.

7 0

3 years ago

The degree measure of one of two complementary angles is twice that of the other. What is one of the degree measures of the angl

IgorC [24]

Answer:

30° is one of the degree measures of the angles.

Hence, option (A) is true.

Step-by-step explanation:

Let 'x' be the degree measure of the first angle.

Given that the degree measure of one of two complementary angles is twice that of the other.

Thus, the other angle = 2x

Complementary angles

We know that two angles are termed as complementary angles when the sum of their measured angles is 90°.

Thus the equation becomes

x + 2x = 90°

3x = 90°

Divide both equations by 3

3x/3 = 90°/3

x = 30°

Therefore, 30° is one of the degree measures of the angles.

Hence, option (A) is true.

3 0

2 years ago

Read 2 more answers