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kodGreya [7K]
3 years ago
10

Carlita saw 5 times as many robins as cardinals while bird watching. She saw a total of 25 birds. How many more robins did she t

han cardinals?
Mathematics
2 answers:
andrew-mc [135]3 years ago
7 0
Carlita was either sipping the hot chocolate while she was out, or else
approximating the numbers.  The exact number she reported is not
possible.  To see why, I'll do it strictly by the math:

Robins  =  5 times
Cardinals  =  1 time

Total birds  =  6 times 

6 times  =  25 birds

Divide each side by 6 :   1 time  =  25/6  =  4-1/6 birds

Robins =  5 times  =  20-5/6 of them
Cardinals  =  1 time  =  4-1/6 of them

Total:  (20-5/6) + (4-1/6)  =  25 birds.

How many more robins than cardinals  = (20-5/6) - (4-1/6) = 16-2/3 more. 

The math works out fine.  But if the numbers she reported are true,
then some of what she saw was partial birds ... legs, or feathers,
things like that.  Eeeew.   I don't want to talk about it.
Alexxx [7]3 years ago
5 0
20 because 5x5=25 so she saw 5 x as many if you divide 5 and 25 you get five
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Answer:

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Step-by-step explanation:

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5 0
3 years ago
An isosceles triangle with base 12mm and perimeter 28mm
olga55 [171]

Answer:

Side lengths of 12,8,8

Step-by-step explanation:

In an isosceles triangle the base is different from the other 2 sides which are the same so

28=12+2x (x being the side of the repeat sides)

14=6+x (divide both sides by 2)

8=x (subtract 6 from both sides) so

Side lengths of 12,8,8

5 0
3 years ago
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Rainbow [258]

By algebra properties we find the following relationships between each pair of algebraic expressions:

  1. First equation: Case 4
  2. Second equation: Case 1
  3. Third equation: Case 2
  4. Fourth equation: Case 5
  5. Fifth equation: Case 3

<h3>How to determine pairs of equivalent equations</h3>

In this we must determine the equivalent algebraic expression related to given expressions, this can be done by applying algebra properties on equations from the second column until equivalent expression is found. Now we proceed to find for each case:

First equation

(7 - 2 · x) + (3 · x - 11)

(7 - 11) + (- 2 · x + 3 · x)

- 4 + (- 2 + 3) · x

- 4 + (1) · x

- 4 + (5 - 4) · x

- 4 - 4 · x + 5 · x

- 4 · (x + 1) + 5 · x → Case 4

Second equation

- 7 + 6 · x - 4 · x + 3

(6 · x - 4 · x) + (- 7 + 3)

(6 - 4) · x - 4

2 · x - 4

2 · (x - 2) → Case 1

Third equation

9 · x - 2 · (3 · x - 3)

9 · x - 6 · x + 6

3 · x + 6

(2 + 1) · x + (14 - 8)

[1 - (- 2)] · x + (14 - 8)

(x + 14) - (8 - 2 · x) → Case 2

Fourth equation

- 3 · x + 6 + 4 · x

x + 6

(5 - 4) · x + (7 - 1)

(7 + 5 · x) + (- 4 · x - 1) → Case 5

Fifth equation

- 2 · x + 9 + 5 · x  + 6

3 · x + 15

3 · (x + 5) → Case 3

To learn more on algebraic equations: brainly.com/question/24875240

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5 0
1 year ago
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Answer:

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Step-by-step explanation:

Volume of the square pyramid is given as ⅓*area of base*height of pyramid.

Where,

Area of base = 6*6 = 36

Height of pyramid = altitude = \sqrt{7} units

Plug the values into the formula to find volume.

Volume = \frac{1}{3}*36*\sqrt{7}

Volume = 12*\sqrt{7}

Volume = 12\sqrt{7} cubic units

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Y_Kistochka [10]

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