No i don't but if u need anything else about this syndrome feel free to ask
Answer:
i. <DCB = 
ii. Sin of <DCB = 0.8
Step-by-step explanation:
Let <DCB be represented by θ, so that;
Sin θ = 
Thus from the given diagram, we have;
Sin θ = 
= 0.8
This implies that,
θ =
0.8
= 53.1301
θ = 
Therefore, <DCB =
.
So that,
Sin of <DCB = Sin 
= 0.8
Sin of <DCB = 0.8