Answer:
There is no statistical evidence at 1% level to accept that the mean net contents exceeds 12 oz.
Step-by-step explanation:
Given that a random sample of ten containers is selected, and the net contents (oz) are as follows: 12.03, 12.01, 12.04, 12.02, 12.05, 11.98, 11.96, 12.02, 12.05, and 11.99.
We find mean = 11.015
Sample std deviation = 3.157
a) 
(Right tailed test)
Mean difference /std error = test statistic
p value =0.174
Since p >0.01, our alpha, fail to reject H0
Conclusion:
There is no statistical evidence at 1% level to accept that the mean net contents exceeds 12 oz.
Answer: the slope would be -4/3 and the y intercept is 2
Step-by-step explanation: you would have to divide both sides by 3 to get y by itself. that leaves you with -4/3x + 2
Question..
Combine like terms to create an equivalent expression.
½ −⅙q +⅚q - ⅓
Answer:
½ −⅙q +⅚q - ⅓ is equivalent to ⅔q + ⅙
Step-by-step explanation:
Given
½ −⅙q +⅚q - ⅓
Required
Equivalence
½ −⅙q +⅚q - ⅓
We start by collecting like terms.
⅚q - ⅙q + ½ - ⅓
Factorize
(⅚ - ⅙)q + ½ - ⅓
((5 - 1)/6)q + ½ - ⅓
(4/6)q + ½ - ⅓
Reduce 4/6 to lowest term
⅔q + ½ - ⅓
Evaluate fraction
⅔q + (3 - 2)/6
⅔q + ⅙
Hence, ½ −⅙q +⅚q - ⅓ is equivalent to ⅔q + ⅙
Answer:
<h2>L=203 yards</h2><h2>W=52 yards</h2>
Step-by-step explanation:
Step one:
given data
perimeter= 510 yards
let the width be x, width=x
length= (4x-5)-----quadruple mean 4 times
Step two:
the expression for perimeter is
P=2L+2W
510=2(4x-5)+2x
510=8x-10+2x
510+10=8x+2x
520=10x
divide both sides by 10
x=520/10
x=52
the width is 52 yards
the lenght is (4x-5)
L=4(52)-5
L=208-5
L=203 yards
