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kkurt [141]
3 years ago
11

The edge town eagle football team is having a tough season. During one game, they lost a total of 62 yards in 8 plays. What is t

he average ball movement per play?
Mathematics
1 answer:
larisa86 [58]3 years ago
3 0
7.75 is the answer just divide
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A gum ball has a radius that is 30mm. The radius of the gumballs spherical hollow core is 28mm. What is the volume of the gum ba
Arada [10]

Answer:

V = 21145.01 mm³

Step-by-step explanation:

Given that:

The radius of the gumball = 30  mm

The radius of the spherical hollow-core = 28 mm

Consider the radius of the gumball to be r_2 and the radius of the spherical hollow-core to be r_1. Then;

The volume of the gumball can be determined by using the formula of a sphere.

V = \dfrac{4}{3}\pi (r_2^3 - r_1^3)

V = \dfrac{4}{3} \times \pi \times (30^3 - 28^3)

V = 21145.01 mm³

5 0
3 years ago
Triangle ABC is transformed to obtain triangle A′B′C′:
GaryK [48]

Answer:

327

Step-by-step explanation:

7 0
3 years ago
Solve the following inequality.
melisa1 [442]

Answer:

A number line going from 27 to 37, open circle at 32, everything to the right is shaded

Step-by-step explanation:

-1/2p < -16

multiply each side by -2 (don't forget to switch inequality symbol)

p > 32

8 0
2 years ago
Read 2 more answers
Please help with imaginary numbers worksheet!
mihalych1998 [28]

Problem 5

<h3>Answer:   6i</h3>

------------------

Explanation:

We have these four identities

  • i^0 = 1
  • i^1 = i
  • i^2 = -1
  • i^3 = -i

Notice how computing i^4 leads us back to 1. So i^4 = i^0. The pattern repeats every 4 terms. So we divide the exponent by 4 and look at the remainder. We ignore the quotient entirely. We can see that 28/4 = 7 remainder 0. Meaning that i^28 = i^0 = 1.

We can think of it like this if you wanted

i^28 = (i^4)^7 = 1^7 = 1

Then the sqrt(-36) becomes 6i

So overall, we end up with the final answer of 6i

=============================================

Problem 6

<h3>Answer:  -3i</h3>

------------------

Explanation:

We'll use the ideas mentioned in problem 5

46/4 = 11 remainder 2

i^46 = i^2 = -1

sqrt(-9) = 3i

The two outside negative signs cancel out, but there's still a negative from -1 we found earlier. So we end up with -3i

In other words, here is one way you could write out the steps

-i^{46}*-\sqrt{-9}\\\\-i^{2}*-3i\\\\i^{2}*3i\\\\-1*3i\\\\-3i\\\\

=============================================

Problem 7

<h3>Answer:   -1</h3>

------------------

Work Shown:

i^10 = i^2 because 10/4 = 2 remainder 2

i^19 = i^3 because 19/4 = 4 remainder 3

i^7 = i^3 because 7/4 = 1 remainder 3

Again, all we care about are the remainders.

i^{10}+i^{19} - i^{7}\\\\i^{2}+i^{3} - i^{3}\\\\i^{2}\\\\-1

=============================================

Problem 8

<h3>Answer:    -1 + i</h3>

------------------

Work Shown:

i^22*i^6 = i^(22+6) = i^28

Earlier in problem 5, we found that i^28 = i^0 = 1

So,

i^1 - \left(i^{22}*i^{6}\right)\\\\i^1 - i^{28}\\\\i^1 - i^{0}\\\\i - 1\\\\-1+i

8 0
2 years ago
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At a local print shop, 14 copies can be made for $4. At this rate, how much would it
JulijaS [17]
Commenting to unlock messages
6 0
3 years ago
Read 2 more answers
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