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gladu [14]
3 years ago
7

If a =1 + r + 7r and b = 1 -r ,find an expression that equals A+ 3B in standard form. Answer: ​

Mathematics
1 answer:
Trava [24]3 years ago
7 0

Answer:

A+3B=4+5r

Step-by-step explanation:

Given that,

A = 1+r+7r

B = 1-r

We need to find an expression that is equal to A+3B.

Putting the values of A and B in A+3B, we get :

A+3B = 1+r+7r + 3(1-r)

=1+8r+3-3r

=(1+3) +(8r-3r)

=4+5r

Hence, the values of A+3B equals 4+5r.

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Vladimir [108]
Vertex of x^2-2x-1 is (1,-2) so B is true
7 0
3 years ago
What is the probability of these events when we randomly select a permutation of {1,2, ..., n} where n≥4? a) 1 precedes 2 c) 1 i
Paraphin [41]

Answer:

a) 1/2

b) 1/n

c) 1/4

Step-by-step explanation:

a) For each permutation, either 1 precedes 2 or 2 precedes 1. For each permutation in which 1 precedes 2, we can swap 1 and 2 to obtain a permutation in which 2 preceds 1. Thus, half of the total permutations will involve in 1 preceding 2, hence, the probability for a permutation having 1 before 2 is 1/2.

c) If 2 is at the start of the permutation, then it is impossible for 1 to be before 2. If that is not the case, then 1 has a probability of 1/n-1 to be exactly in the position before 2. We can divide in 2 cases using the theorem of total probability,

P( 1 immediately preceds 2) = P (1 immediately precedes 2 | 2 is at position 1) * P(2 is at position 1) + P(1 immediately precedes 2 | 2 is not at position 1) * P(2 is not at position 1) = 0 * 1/n + (1/n-1)*(n-1/n) = 1/n.

d) We can divide the total of permutations in 4 different groups with equal cardinality:

  • Those in which n precedes 1 and n-1 precedes 2
  • those in which n precedes 1 and 2 precedes n-1
  • those in which 1 precedes n and n-1 precedes 2
  • those in which 1 precedes n and 2 precedes n-1

All this groups have equal cardinality because we can obtain any element from one group from another by making a permutations between 1 and n and/or 2 and n-1.

This means that the total amount of favourable cases (elements of the first group) are a quarter of the total, hence, the probability of the event is 1/4.

3 0
3 years ago
The volume of a sphere is a function of its radius. V equals 4 over 3 πr cubed . Evaluate the function for the volume of a volle
Nataly_w [17]

Answer:

The answer to your questin is:  V = 5276.7 cm³

Step-by-step explanation:

Data

radius = 10.8 cm

Volume = ?

Formula

                V = \frac{4}{3} \pi  r^{3}

                V = \frac{4}{3} \pi  (10.8)^{3}

                      V = 5276.7 cm³

4 0
3 years ago
Two angles in a triangle add up to 98 degrees . What is the size of the third angle ?
ira [324]
First you must know that the sum of the interior angles of a triangle are 180.  Once you know that, you just simply add 98+x=180 (you can use an variable as you see fit, doesn't need to be x). And then you simply solve for x by dividing 98 on both sides leaving you with 82.
8 0
3 years ago
The equation of circle having a diameter with endpoints (-2, 1) and (6, 7) is
densk [106]

Answer:

(x-2)^{2}+(y-4)^{2}=25

Step-by-step explanation:

step 1

Find the diameter of the circle

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

A(-2,1)\\B(6,7)  

substitute the values

d=\sqrt{(7-1)^{2}+(6+2)^{2}}

d=\sqrt{(6)^{2}+(8)^{2}}

d=\sqrt{100}

d=10\ units

The radius is half the diameter

so

r=10/2=5\ units

step 2

Find the center of the circle

the center of the circle is the midpoint between the endpoints of the diameter

so

The center is

(\frac{-2+6}{2},\frac{1+7}{2})

(2,4)

step 3

Find the equation of the circle

The equation of the circle is

(x-h)^{2}+(y-k)^{2}=r^{2}

substitute the values

(x-2)^{2}+(y-4)^{2}=5^{2}

(x-2)^{2}+(y-4)^{2}=25

8 0
3 years ago
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