Step-by-step explanation:
Yes they are equivalent. You get -3 when you try solving the actual equation.
Answer:
C = 1.41n
Step-by-step explanation:
you have to multiply 1.41 by the weight(n)
The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
Learn more about work done here:
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Answer:
-25/12
Step-by-step explanation:
first, you need a common denominator. in this case, it's 12.
-1/3=-4/12
-7/4=-21/12
and then you add
-4+-21=-25
so -25/12 is your answer