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Mashutka [201]
4 years ago
10

the initial population of a town is 16,237 and it grows with a doubling time of 24 years. what will the popluation be in 2 years

.
Mathematics
1 answer:
Mamont248 [21]4 years ago
7 0

Answer: 17,203 people

Step-by-step explanation:

The formula for solving this is;

P(t) = P_{0} (2)^{t/dt}

Where;

P(t) is the population at time t

P_{0} is the initial population

t is the year of interest

dt is the amount of time it takes to double.

P(t) = P_{0} (2)^{t/dt}

P(2) = 16,237 (2)^{2/24}

=  17,202.50

= 17,203 people

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Step-by-step explanation:

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4 0
3 years ago
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xeze [42]

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Step-by-step explanation:

<u>Step 1</u>:-

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<u>step 2:</u>-

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5 0
4 years ago
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MrRissso [65]

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Step-by-step explanation:

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x=

7

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​

2 Substitute x=\frac{4(y-3)}{7}x=

7

4(y−3)

​

 into 9x-4y=-209x−4y=−20.

\frac{36(y-3)}{7}-4y=-20

7

36(y−3)

​

−4y=−20

3 Solve for yy in \frac{36(y-3)}{7}-4y=-20

7

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​

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7

4(y−3)

​

.

x=-4

x=−4

5 Therefore,

\begin{aligned}&x=-4\\&y=-4\end{aligned}

​

 

x=−4

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​

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