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azamat
3 years ago
13

How pure is 16-karat gold?

Mathematics
2 answers:
jonny [76]3 years ago
5 0

Answer:

About 67% because karats are on a scale of 1-24 with 24 being pure gold,

so 16/24.

natta225 [31]3 years ago
3 0

Answer:

here

Step-by-step explanation:

16 karat gold is 16 parts gold to 8 parts other material for a pure gold percentage of 67%.

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Step-by-step explanation:

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What is the measure of Angle z?
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Step-by-step explanation:

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3 years ago
A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student
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Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

The information provided is as follows:

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The critical value of <em>z</em> for 98% confidence level is,

z_{\alpha/2}=z_{0.02/2}=2.326

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

     =(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

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2 years ago
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