Answer:
168?
Step-by-step explanation:
Im not for sure but these are my steps...
560 x .30 = 168
The slope of the line of best fit to the raw-score scatter plot is 0.98
- The equation is y = 0.98x - 3.74
- The value of y given that x = 12 is 8.02
<h3>How to determine the slope of the line?</h3>
From the question, we have the following parameters that can be used in our computation:
- Standard deviations of X, Sx = 1.88
- Standard deviations of Y, Sy =2.45
- Correlation coefficient, r between X and Y = 0.75
The slope (b) of the line is calculated as
b = r * Sy/Sx
Substitute the known values in the above equation, so, we have the following representation
b = 0.75 * 2.45/1.88
Evaluate
b = 0.98
<h3>The equation of the line of best fit</h3>
A linear equation is represented as
y = bx + c
Where
Slope = b
y-intercept = c
In (a), we have
b = 0.98
So, we have
y = 0.98x + c
Recall that the point (13, 9) is on the line of best fit.
So, we have
9 = 0.98 * 13 + c
This gives
9 = 12.74 + c
Evaluate
c = -3.74
So, we have
y = 0.98x - 3.74
<h3>The value of y from x</h3>
Here, we have
x = 12
So, we have
y = 0.98 x 12 - 3.74
Evaluate
y = 8.02
Read more about line of best fit at
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To group an expression, means that the factors of the expression are to be separated in (), [] or {}.
An expression with a value of 80 is: ![2^2 \times ( [2 + 2] \times [3 + 2] )](https://tex.z-dn.net/?f=2%5E2%20%5Ctimes%20%28%20%5B2%20%2B%202%5D%20%5Ctimes%20%5B3%20%2B%202%5D%20%29)
The number is given as:
Factorize
Factorize 40
Express 
as an exponent
Express 20 as 4 x 5
Express 5 as 3 + 2
![80 = 2^2 \times ( 4 \times [3 + 2] )](https://tex.z-dn.net/?f=80%20%3D%202%5E2%20%5Ctimes%20%28%204%20%5Ctimes%20%5B3%20%2B%202%5D%20%29)
Express 4 as 2 + 2
![80 = 2^2 \times ( [2 + 2] \times [3 + 2] )](https://tex.z-dn.net/?f=80%20%3D%202%5E2%20%5Ctimes%20%28%20%5B2%20%2B%202%5D%20%5Ctimes%20%5B3%20%2B%202%5D%20%29)
Hence, the above expression has a numerical value of 80
Read more about numerical expressions at:
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Answer:
8, 2
Step-by-step explanation:
8 * 2 = 16
8 + 2 = 10
Perpendicular lines will have negative reciprocal slopes
B. y = -4x+ 5 and y = 1/4x + 4
D. y = x + 4 and y = -x + 4
E. y = -3 and x = -3
