All categories

3 years ago

|2x-3|=5 Absolute value

Mathematics

2 answers:

matrenka [14]3 years ago

4 0

Answer:

this is the answer I hope it helps

x= 4,-1

sineoko [7]3 years ago

3 0

Answer:

x = 4, x = - 1

Step-by-step explanation:

The absolute value always gives a positive result, however, the expression inside can be positive or negative, that is

2x - 3 = 5 or - (2x - 3) = 5

Solving both

2x - 3 = 5 ( add 3 to both sides )

2x = 8 ( divide both sides by 2 )

x = 4

- (2x - 3) = 5

- 2x + 3 = 5 ( subtract 3 from both sides )

- 2x = 2 ( divide both sides by - 2 )

x = - 1

As a check

| 2(4) - 3 | = | 8 - 3 | = | 5 | = 5 ← True

| 2(- 1) - 3 | = | - 2 - 3 | = | - 5 | = 5 ← True

Thus the solutions are x = 4, x = - 1

You might be interested in

For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.

Anni [7]

Answer:

The reduced row-echelon form of the linear system is $\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

Interchange two rows
Multiply one row by a nonzero number
Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

$\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]$

You need to follow these steps:

Divide row 1 by 2 $\left(R_1=\frac{R_1}{2}\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]$

Subtract row 1 from row 2 $\left(R_2=R_2-R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]$

Subtract row 1 multiplied by 5 from row 3 $\left(R_3=R_3-\left(5\right)R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 1 $\left(R_1=R_1-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 3 $\left(R_3=R_3-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]$

Multiply row 2 by 2 $\left(R_2=\left(2\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]$

Divide row 3 by −19 $\left(R_3=\frac{R_3}{-19}\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]$

Subtract row 3 multiplied by 16 from row 1 $\left(R_1=R_1-\left(16\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]$

Add row 3 multiplied by 6 to row 2 $\left(R_2=R_2+\left(6\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

8 0

3 years ago

You and 4 of your friends want to make some soup for lunch each person would like to eat 1 1/3 cup soup how many cups of soup wi

Pavlova-9 [17]

Multiply the amount of people by the amount of cups they want

4*1 1/3=5 1/3
You would have to make 5 and 1/3 cups of soup

Hope this helps!

4 0

3 years ago

Read 2 more answers

PLEASE HELP WILL GIVE BRAINLY IF U HELP ME

konstantin123 [22]

Answer:

Step-by-step explanation:

8 0

2 years ago

Evaluate 5x – 2y + (7x – y) for x = 7 and y = –2

Lynna [10]

Answer:

Step-by-step explanation:

5x – 2y + (7x – y)

Combine like terms

12x -3y

Let x = 7 and y = -2

12(7) -3(-2)

84 +6

6 0

2 years ago

Read 2 more answers

Need the answer for x and y

Hunter-Best [27]

Answer:

x = 6

CD = 59

Step-by-step explanation:

10x - 1 = 8x + 11

combine like terms:

2x = 12

x = 6

CD = 8(6) + 11 = 59

5 0

3 years ago