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3 years ago

Find the value of x. Round to the nearest tenth. 26 12 Х x = [ ?

Mathematics

1 answer:

Snezhnost [94]3 years ago

4 0

Answer:

x = 10.8

Step-by-step explanation:

cos 26° = x/12

0.8988 = x/12

x = 10.785

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The mean sustained wind velocity, v, can be determined by the equation v = 6.3 StartRoot 1013 minus p EndRoot, where p is the ai

olya-2409 [2.1K]

Answer:

910 millibars

Step-by-step explanation:

According to the Question,

Given That, The mean sustained wind velocity equation $v=6.3*\sqrt{1013-p}$ And The mean sustained wind velocity is 64m/s (v=64) . where, p is the air pressure(in millibars).

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on squaring both sides we get,

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A small plane and a large plane are 6.8km from each other, at the same altitude (height). From an observation tower, the two air

Lemur [1.5K]

Answer:

7.9km

Step-by-step explanation:

(a)See attached for the diagram representing this situation.

(b)

In Triangle ABC

$\text{Using Law of Sines}\\\dfrac{\sin A}{a}=\dfrac{\sin C}{c} \\\dfrac{\sin A}{5.2}=\dfrac{\sin 58^\circ}{6.8} \\\sin A=5.2 \times \dfrac{\sin 58^\circ}{6.8}\\A=\arcsin (5.2 \times \dfrac{\sin 58^\circ}{6.8})\\A=40.43^\circ$

Next, we determine the value of Angle B.

$\angle A+\angle B+\angle C=180^\circ\\40.43+58+\angle B=180^\circ\\\angle B=180^\circ-(40.43+58)\\\angle B=81.57^\circ$

Finally, we find b.

$\text{Using Law of SInes}\\\dfrac{b}{\sin B}=\dfrac{c}{\sin C} \\\dfrac{b}{\sin 81.57^\circ}=\dfrac{6.8}{\sin 58^\circ} \\b=\dfrac{6.8}{\sin 58^\circ} \times \sin 81.57^\circ\\b=7.9km $ (to the nearest tenth of a kilometer)$

The distance between the small plane and the observation tower is 7.9km.

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4 years ago

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