Question

The mean sustained wind velocity, v, can be determined by the equation v = 6.3 StartRoot 1013 minus p EndRoot, where p is the air pressure, in millibars, at the center of the hurricane. What is the approximate air pressure at the center of a hurricane when the mean sustained wind velocity is 64 meters per second? 103 millibars 194 millibars 363 millibars 910 millibars

Answer 1

Answer:

910 millibars

Step-by-step explanation:

According to the Question,

• Given That, The mean sustained wind velocity equation $v=6.3*\sqrt{1013-p}$ And The mean sustained wind velocity is 64m/s (v=64) . where, p is the air pressure(in millibars).

Now, the air pressure at the center of a hurricane when the mean sustained wind velocity is 64 m/s is

$64=6.3*\sqrt{1013-p}\\\frac{64}{6.3} = \sqrt{1013-p}$

on squaring both sides we get,

(10.1587)² = 1012 - p  ⇒ p = 908.80≈910millibar

p = 910millibars air pressure .

Answer 2

Answer:

p = 910millibars on edg

Step-by-step explanation: