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2 years ago

Plzzzzzzzzzzzzzzzzzzzzzzz

Mathematics

1 answer:

Ahat [919]2 years ago

6 0

Answer:

Step-by-step explanation:

7x-14-2x+6 = 5x - 8

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Whats is 4 hundreds 13 tens 5 ones in standard form

mars1129 [50]

4 hundreds 13 tens 5 ones = 400+13*10+5
= 400+130+5
= 535

6 0

2 years ago

What’s the answer? (Due today by 7pm) Thanks!!

AnnZ [28]

Answer:

90 x 1/2 = 45 km

The rate is 90 miles per hour and 30/60=1/2 so we multiply 1/2

Hope this helps

Step-by-step explanation:

5 0

2 years ago

100 POINTS GEOMETRY WORK

oksano4ka [1.4K]

Number 3 is 100 number 4 is 112

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2 years ago

5. An attacker swings a board with a mass of 2 kg toward a victim. The acceleration is 10 m/s2 when the board hits the victim. H

suter [353]

The force exerted on victim is 20 newton

Solution:

An attacker swings a board with a mass of 2 kg toward a victim

The acceleration is 10 $m/s^2$ when the board hits the victim

To find: Force exerted on victim

The force is given by formula:

$F = mass \times acceleration$

From given,

$mass = 2 \text{ kg }\\\\Acceleration = 10$ $m/s^2$

Substituting the values in formula,

$Force = 2 \times 10 = 20$

Thus force exerted on victim is 20 newton

6 0

2 years ago

A computer programmer has an 18% chance of finding a bug in any given program. What is the probability that she does not find a

LiRa [457]

Answer: $(\frac{41}{50})^{10}$

Step-by-step explanation:

Since, According to the question,

The chance of finding a bug in a program = 18%

Thus, the probability of finding the bug in first attempt = $\frac{18}{100}=\frac{9}{50}$

⇒ The probability of not finding any bug in first attempt = $1 - \frac{9}{50} =\frac{41}{50}$

Similarly, in second attempt , third attempt, fourth attempt_ _ _ _ _ tenth attempt, the probability of not finding any bug is also equal to $\frac{41}{50}$

Thus, the probability that she does not find a bug within the first 10 programs she examines

= $\frac{41}{50}\times \frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}\times\frac{41}{50}$

= $(\frac{41}{50})^{10}$

5 0

3 years ago