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alexgriva [62]
2 years ago
5

Find the range for the given domain: {-3,-1 and 3} and the function is y=3x^2-2x+1.

Mathematics
1 answer:
Artist 52 [7]2 years ago
7 0

Answer:

D

Step-by-step explanation:

The domain are the x values. When you plug those values into the equation, you get 34, 6, 22.

3(-3²) - 2(-3) + 1                     Negative * Negative = Positive

3(9) + 6 + 1

34

3(-1²) - 2(-1) + 1

3 + 2 +1

6

3(3²) -2(3) + 1

3(9) - 6 + 1

22

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Elodia [21]

The inverse of the function f(x)  = 4(x-3)² + 2 is f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

The given function is:

f(x)   =  4(x  - 3)²  +  2

To find the inverse of the function:

Make x as the subject of the formula

4(x-3)^2 = f(x) - 2\\(x-3)^2 = \frac{f(x)-2}{4} \\x - 3 = \sqrt{\frac{f(x)-2}{4} } \\x = \sqrt{\frac{f(x)-2}{4} } + 3

Replace x by f^{-1}(x) and replace f(x) by x

f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

Therefore, the inverse of the function is:

f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

Learn more here: brainly.com/question/17285960

4 0
2 years ago
Can someone please help me!
Sindrei [870]

Answer:

The Answer is x=6 2/3

Step-by-step explanation:

The Area of a triangle is A= 1/2 bh, so we should think of the triangle as half of a square/rectangle. This means the total area of the theoritical Square is 400 sq ft. We then figure out this equation:

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Hope this helps!

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Answer:

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