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kirill [66]
2 years ago
6

Fraction

Mathematics
1 answer:
adelina 88 [10]2 years ago
5 0

Answer:

A=6/5

B=0.111

C=166 2/3%

Step-by-step explanation:

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The product of x and 9 equals 45
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Seven pieces of rope have an average (arithmetic mean) length of 68 centimeters and a median length of 84 centimeters. If the le
Svet_ta [14]

Answer:

The maximum possible length, in centimeters, of the longest piece of rope is 134 cm

Step-by-step explanation:

Let the seven pieces be a,b,c,d,e,f,g

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Average = \frac{\text{Sum of all lengths}}{\text{No. of pieces}}

68= \frac{\text{Sum of all lengths}}{7}

68 \times 7 =\text{a+b+c+d+e+f+g}

476=\text{a+b+c+d+e+f+g} --A

We are given that the median length of a piece of rope is 84 centimeters.

We arrange the pieces in the ascending order

So, median will be the length of 4th piece

So, d = 84 cm

the length of piece a,b,c will be less than 84 and the value of e,f,g must be greater than or equal to 84

Let us suppose the length of a,b,c be x

Let us suppose the length of e,f be 84

The length of the longest piece of rope is 14 centimeters more than 4 times the length of the shortest piece of rope

So, g = 4x+14

Substitute the value in A

476=x+x+x+84+84+84+4x+14

476=7x+266

\frac{476-266}{7}=x

30=x

g = 4x+14=4(30)+14=134

Hence the maximum possible length, in centimeters, of the longest piece of rope is 134 cm

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Please leave a thanks.

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