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3 years ago

Collect like terms − 8 d 2 − 3 d 2

Mathematics

2 answers:

STALIN [3.7K]3 years ago

7 0

Answer:

8,2,2,3

d,d,

HOPE THIS HELPS

Norma-Jean [14]3 years ago

4 0

Answer:

5d²

Step-by-step explanation:

Given

8d² - 3d² ← collect like terms by subtracting the coefficients, that is

(8 - 3)d²

= 5d²

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Answer:

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Step-by-step explanation:

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3 years ago

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Fofino [41]

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4 years ago

What is the measure of angle A ?<br> what is the measure of angle B ?

lesya692 [45]

Answer:

$\angle\,A=72^o\\\angle\,B=108^o$

Step-by-step explanation:

Notice that buy construction of a parallelogram,the angles $\angle \,A$ and $\angle \,C$ must equal each other. Then, based on the info given, we can write the following equation:

$3\,y+27^o=5\,y-3^o\\27^o+3^o=5\,y-3\,y\\30^o=2\,y\\y=15^o$

Then, angle $\angle \,A$ = $5\,(15^o)-3^o=72^o$ which is also equal to angle B

and since the addition of all internal angles of the parallelogram must equal $360^o$ , then:

$B+D=360^o-72^o-72^o=216^o$

and therefore, since $\angle \,B$ and $\angle \,D$ must be equal, then:

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3 years ago

To estimate the mean height μ of male students on your campus, you will measure an SRS of students. You know from government dat

denis-greek [22]

Answer:

a) The standard deviation of x must be 0.25 inches.

b) We need a sample of 125 to reduce the standard deviation of x⎯⎯⎯ to the value you found in part(a).

Step-by-step explanation:

The 68-95-99.7 states that:

68% percent of the measures of a normally distributed sample are within 1 standard deviation of the mean.

95% percent of the measures of a normally distributed sample are within 2 standard deviations of the mean.

99.7% percent of the measures of a normally distributed sample are within 3 standard deviations of the mean.

The standard deviation of the population is 2.8. This means that $\sigma = 2.8$ .

(a) What standard deviation must x⎯⎯⎯ have so that 95% of all samples give an x⎯⎯⎯ within one-half inch of μ?

We want to have a sample in which 2 standard deviations are within 0.5 inches of the mean.

So, the standard deviation of the sample must be:

$2s = 0.5$

$s = 0.25$

The standard deviation of x must be 0.25 inches.

(b) How large an SRS do you need to reduce the standard deviation of x⎯⎯⎯ to the value you found in part(a)?

We have that the standard deviation of a sample of length n is given by the following formula:

$s = \frac{\sigma}{\sqrt{n}}$ .

We want $s = 0.25$ and we have $\sigma = 2.8$ . So

$0.25 = \frac{2.8}{\sqrt{n}}$

$0.25\sqrt{n} = 2.8$

$\sqrt{n} = 11.2$

$\sqrt{n}^{2} = (11.2)^{2}$

$n = 125.44$

We need a sample of 125 to reduce the standard deviation of x⎯⎯⎯ to the value you found in part(a).

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4 years ago

Math help pls thank u

ELEN [110]

(8) =b

explaintion is : 3 seven times is 21

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3 years ago