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WARRIOR [948]
3 years ago
7

Which number line represents the solutions to -2]x1 = -6?

Mathematics
1 answer:
Ilya [14]3 years ago
8 0

Answer

Step-by-step explanation:

B - 8-7-6-5-4-3-2-1-0 234 567 8 8

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2m= cm <br><br><br> Pls help me!!!
Andrej [43]

Answer:

200cm

Step-by-step explanation:

6 0
2 years ago
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Geometry question!!
Mademuasel [1]

Answer:

GQ=25 units

Step-by-step explanation:

we know that

Point Q is the midpoint of GH

so

GH=GQ+QH  and  GQ=QH

GH=2GQ -------> equation A

we have

GH=5x-5

GQ=2x+3

substitute in the equation A and solve for x

5x-5=2(2x+3)

5x-5=4x+6

5x-4x=6+5

x=11

Find the length of GQ

GQ=2x+3

substitute the value of x

GQ=2(11)+3

GQ=25 units

4 0
3 years ago
What is 1.5 m - 5 cm ?
Alenkasestr [34]

Answer:

1.45 m

Step-by-step explanation:

Convert 1.5 metre into cm

1.5 metre =150 center meters

150 cm -5=145

145 into metres is 1.45 m

7 0
3 years ago
Please give me the answer
Tcecarenko [31]

Answer:

7 units

Step-by-step explanation:

hope I helped today

8 0
3 years ago
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The total stopping distance T for a vehicle is T = 2.5x + 0.5x 2 , where T is in feet and x is the speed in miles per hour. Appr
Kobotan [32]

Answer:

%  change in stopping distance = 7.34 %

Step-by-step explanation:

The stooping distance is given by

T = 2.5 x + 0.5 x^{2}

We will approximate this distance  using the relation

f (x + dx) = f (x)+ f' (x)dx

dx = 26 - 25 = 1

T' =  2.5 + x

Therefore

f(x)+f'(x)dx = 2.5x+ 0.5x^{2} + 2.5 +x

This is the stopping distance at x = 25

Put x = 25 in above equation

2.5 × (25) + 0.5× 25^{2} + 2.5 + 25 = 402.5 ft

Stopping distance at x = 25

T(25) = 2.5 × (25) + 0.5 × 25^{2}

T(25) = 375 ft

Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft

%  change in stopping distance = \frac{27.5}{375} × 100

%  change in stopping distance = 7.34 %

6 0
3 years ago
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