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Shkiper50 [21]
3 years ago
6

For each scenario, select the best solution to try from the drop-down menu. A computer will not connect to the network. An IP ad

dress is being used by more than 1 computer. A router does not appear to be working at all. Some network files have become damaged.

Computers and Technology
1 answer:
Inessa05 [86]3 years ago
6 0

Answer:

1) Check the switches, routers, and hubs.

2) Try logging off and on again.

3) Make sure everything is plugged in and turned on.

4) Restore files from backup versions.

Explanation:

Hope this helped!! :D

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6 0
3 years ago
Assume that a large number of consecutive IP addresses are available starting at 198.16.0.0 and suppose that two organizations,
Fiesta28 [93]

Answer & Explanation:

An IP version 4 address is of the form w.x.y.z/s

where s = subnet mask

w = first 8 bit field, x = 2nd 8 bit field, y = 3rd 8 bit field, and z = 4th 8 bit field

each field has 256 decimal equivalent. that is

binary                                        denary or decimal

11111111      =        2⁸      =             256

w.x.y.z represents

in binary

11111111.11111111.11111111.11111111

in denary

255.255.255.255

note that 255 = 2⁸ - 1 = no of valid hosts/addresses

there are classes of addresses, that is

class A = w.0.0.0 example 10.0.0.0

class B = w.x.0.0 example 172.16.0.0

class C = w.x.y.0 example 198.16.8.1

where w, x, y, z could take numbers from 1 to 255

Now in the question

we were given the ip address : 198.16.0.0 (class B)

address of quantity 4000, 2000, 8000 is possible with a subnet mask of type

255.255.0.0 (denary) or

11111111.11111111.00000000.00000000(binary) where /s =  /16 That is no of 1s

In a VLSM (Variable Length Subnet Mask)

Step 1

we convert the number of host/addresses for company A to binary

4000 = 111110100000 = 12 bit

step 2 (subnet mask)

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11110000.000000                /20

now we have added 4 1s in the 3rd field to reserve 12 0s

<u><em>subnet mask: 255.255.</em></u><u><em>16.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1       1      </em></u><u><em> 1 </em></u><u><em>      1     1     1     1</em></u>

<u><em>128  64     32    </em></u><u><em>16</em></u><u><em>    8    4     2    1</em></u>

step 3

in the ip network address: 198.16.0.0/19 <em>(subnet representation)</em> we increment this using 16

that is 16 is added to the 3rd field as follows

That means the ist Valid Ip address starts from

          Ist valid Ip add: 198.16.0.1 - 198.16.15.255(last valid IP address)

Company B starts<u><em>+16: 198.16.</em></u><u><em>16</em></u><u><em>.0 - 198.16.31.255</em></u>

<u><em>                   +16: 198.16.</em></u><u><em>32</em></u><u><em>.0- 198.16.47.255 et</em></u>c

we repeat the steps for other companies as follows

Company B

Step 1

we convert the number of host/addresses for company B to binary

2000 = 11111010000 = 11 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 11 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11111000.000000                /21

now we have added 5 1s in the third field to reserve 11 0s

<u><em>subnet mask: 255.255.</em></u><u><em>8.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1       1       1       </em></u><u><em>1 </em></u><u><em>    1     1     1</em></u>

<u><em>128  64     32    16    </em></u><u><em>8 </em></u><u><em>   4     2    1</em></u>

Step 3

Starting from after the last valid Ip address for company A

in the ip network address: 198.16.16.0/21 (<em>subnet representation</em>) we increment this using 8

That means the ist Valid Ip address starts from

           Ist valid Ip add: 198.16.16.1 - 198.16.23.255(last valid IP address)

Company C starts <u><em>+16: 198.16.</em></u><u><em>24</em></u><u><em>.0- 198.16.31.255</em></u>

<em>                             </em><u><em> +16: 198.16.</em></u><u><em>32</em></u><u><em>.0- 198.16.112.255 et</em></u>c

Company C

Step 1

we convert the number of host/addresses for company C to binary

4000 = 111110100000 = 12 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11110000.000000                /20

now we have added 4 1s in the 3rd field to reserve 12 0s

<u><em>subnet mask: 255.255.</em></u><u><em>16.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1       1       1       1     1     1     1</em></u>

<u><em>128  64     32    16    8    4     2    1</em></u>

Step 3

Starting from after the last valid ip address for company B

in the ip network address: 198.16.24.0/20 (subnet representation) we increment this using 16

That means the ist Valid Ip address starts from

           Ist valid Ip add: 198.16.24.1 - 198.16.39.255(last valid IP address)

Company C starts <u><em>+16: 198.16.40.0- 198.16.55.255</em></u>

<em>                          </em><u><em>    +16: 198.16.56.0- 198.16.71.255 et</em></u>c

Company D

Step 1

we convert the number of host/addresses for company D to binary

8000 = 1111101000000 = 13 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 13 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000            /16

variable subnet mask: 11111111.11111111.11100000.000000                /19

now we have added 3 1s in the 3rd field to reserve 13 0s

<u><em>subnet mask: 255.255.</em></u><u><em>32.</em></u><u><em>0 (where the 1s in each field represent a denary number as follows)</em></u>

<u><em>1st 1 = 128, 2nd 1 = 64 as follows</em></u>

<u><em>1        1      </em></u><u><em> 1 </em></u><u><em>      1       1     1     1     1</em></u>

<u><em>128  64     </em></u><u><em>32  </em></u><u><em>  16    8    4     2    1</em></u>

Step 3

Starting from after the last valid ip address for company C

in the ip network address: 198.16.40.0/20 (subnet representation) we increment this using 32

That means the ist Valid Ip address starts from

           Ist valid Ip add: 198.16.40.1 - 198.16.71.255(last valid IP address)

Company C starts <u><em>+16: 198.16.72.0- 198.16.103.255</em></u>

<em>                          </em><u><em>    +16: 198.16.104.0- 198.16.136.255 et</em></u>c

5 0
3 years ago
Zadanie nr 1
Gennadij [26K]

Answer:

Explanation:

Rezonans, Obiekt bez wibracji ma tendencję do robienia tego z określoną częstotliwością zwaną naturalną lub rezonansową częstotliwością obiektu. (Ta częstotliwość zależy od wielkości, kształtu i składu przedmiotu). Taki przedmiot będzie silnie wibrował, gdy zostanie poddany wibracjom lub regularnym impulsom o częstotliwości równej lub bardzo zbliżonej do swojej częstotliwości naturalnej. Zjawisko to nazywa się rezonansem. Dzięki rezonansowi stosunkowo słaba wibracja w jednym obiekcie może powodować silne wibracje w innym. Analogicznie termin rezonans jest również używany do opisania zjawiska, w którym oscylujący prąd elektryczny jest wzmacniany sygnałem elektrycznym o określonej częstotliwości.

Przykład rezonansu zapewnia silnik, który powoduje wibracje mebla w innej części tego samego domu. Drgania te występują, ponieważ częstotliwość naturalna mebli jest równa częstotliwości drgań ustawianych przez silnik. Mówi się, że meble rezonują z silnikiem. Rezonans można również zaobserwować w samochodzie, gdy pewna popielniczka Partan, na przykład wibruje, gdy samochód jedzie z określoną prędkością. Popielniczka rezonuje z wibracjami silnika przy tej prędkości.

Rezonans mechaniczny może wytwarzać wibracje wystarczająco silne, aby zniszczyć obiekt, w którym występują. Na przykład żołnierze maszerujący nad mostem mogą wytwarzać ekstremalne wibracje z częstotliwością naturalną mostu i roztrzaskiwać go na części. Z tego powodu żołnierze przebijają się, by przejść przez most. W 1940 r. Podmuchy wiatru w Puget Sound Narrows w Tacoma w stanie Waszyngton spowodowały, że most wiszący wibruje z naturalną częstotliwością i most zawalił się.

W muzyce rezonans służy do zwiększenia intensywności (głośności) dźwięku. Na przykład stosunkowo słabe wibracje wytwarzane na końcu rurki organowej powodują, że kolumna powietrza w rurze wibruje w rezonansie, znacznie zwiększając głośność dźwięku. Zasada ta dotyczy także głosu ludzkiego, w którym wibracje strun głosowych są wzmacniane przez wibracje rezonansowe w kanałach ustnych i nosowych.

Rezonans elektryczny służy do strojenia radiotelefonów i telewizorów. Strojenie polega na ustanowieniu obwodu o częstotliwości rezonansowej równej przydzielonej częstotliwości żądanej stacji.

6 0
3 years ago
You provide desktop support for a small company. The company has two locations in the same city, but they are several miles away
wel

Answer:

access the computer remotely

Explanation:

The best option would be to access the computer remotely. This allows you to remotely view the computer and control it from anywhere in the world. This allows you to take full control, analyze, and fix the problem that the individual is having without having to explain step by step to the user what they have to do. This can be accomplished through a direct IP connection or through a third-party software, which the user will need to have installed on their computer.

5 0
3 years ago
Many documents use a specific format for a person's name. Write a program whose input is: firstName middleName lastName, and who
never [62]

Answer:

Python Program:

if __name__ == '__main__':

   a = input("Enter Name: ")

   b = a.split()

   print(b[2] + ',' , b[0], b[1][0])

Explanation:

The input function will be used to prompt user to enter the name of the person. The person's name will be stored in variable a.

Let us assume that the user entered a name mentioned in the example, which is Pat Silly Doe, Now variable a = 'Pat Silly Doe'.

The function a.split() is used to split a string into a list. The splitting (by default) is done on the basis of white-space character. Therefore, a.split() will give a list

['Pat', 'Silly', 'Doe']

which will be later on stored in variable b.

We can use the subscript operator [] to access the values in a list. Suppose if we have a list a, then a[i] will give us ith element of a, if i < length of a.

Finally, we print the answer. b[2] will give us the last name of the person. We append a comma using '+' operator. b[0] will give us the first name. b[1] will give us the middle name, but since we only need one character from the middle name, we can use another subscript operator b[1][0] to give us the first character  of the middle name.

Note: Characters of strings can be accessed using subscript operator too.

4 0
3 years ago
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