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Harman [31]
3 years ago
13

PLS HURRY!! Look at the image below!

Computers and Technology
1 answer:
Verizon [17]3 years ago
6 0

Answer:

control

Explanation:

You might be interested in
simplify the expression below and state the value of m for which the simplified expression is not defined 2m² + m - 15/ m² - 9​
motikmotik

Answer:

  • The simplified expression is: \frac{2m-5}{m-3}
  • The simplified expression is undefined for m=3

Explanation:

The given expression is:

\frac{2m^2+m-15}{m^2-9}

The numerator can be siplified by using factorization and denominator will be simplified using the formula

a^2-b^2 = (a+b)(a-b)

So,

= \frac{2m^2+6m-5m-15}{(m)^2-(3)^2}\\=\frac{2m(m+3)-5(m+3)}{(m-3)(m+3)}\\=\frac{(2m-5)(m+3)}{(m-3)(m+3)}\\=\frac{2m-5}{m-3}

A fraction is undefined when the denominator is zero. In order to find the value of m on which the simplified fraction will be undefined we will put denominator equal to zero.

So,

m-3 = 0 => m = 3

Hence,

  • The simplified expression is: \frac{2m-5}{m-3}
  • The simplified expression is undefined for m=3
7 0
3 years ago
Imagine you are responsible for making a presentation that includes a representation of the logic flow through a process. You un
svetoff [14.1K]

Answer:

find reliable resources

Explanation:

if you find reliable resources, than you might able to have more help i know im not answering..but im trynna help

3 0
3 years ago
The base class Pet has private fields petName, and petAge. The derived class Dog extends the Pet class and includes a private fi
Lapatulllka [165]

Answer:

Hello attached is the Java program written to solve the problem

The Pet.java and Dog.java files are unaltered

Explanation:

The input and output  codes are attached as well i.e the second image is the input while the third image is the output code

5 0
3 years ago
Which of the following is non-volatile storage?
gulaghasi [49]
Primary because it is non-volatile storage
6 0
3 years ago
Write the function definition for a function called list_total that accepts a list of integers
uranmaximum [27]

Answer:

def list_total(numbers):

   sum_of_numbers = 0

   for number in numbers:

       sum_of_numbers += number

   return sum_of_numbers

Explanation:

So, to define a function, the syntax is simply:

def functionName(arguments here):

   # code

So to define a function called "list_total" which accepts a list of integers, you write:

"

def list_total(numbers):
   # code

"

any the "numbers" is a parameter, and it's just like any variable, so you can name it anything besides keywords. I just named it "numbers" since it makes sense in this context, you could also write "integers" instead and it would be just as valid, and may be a bit more specific in this case.

Anyways from here, the initial sum should be equal to 0, and from there we add each number in the list to that initial sum. This can be done by initializing a variable to the value "0" and then traversing the list using a for loop. This can be done as such:

"

def list_total(numbers):

   sum_of_numbers = 0

   for number in numbers:

       # code

"

So for each element or integer in the list "numbers" the for lop will run, and the variable "number" will contain the value of the current element it's on.

So we can add the "number" to the sum_of_numbers as such:

sum_of_numbers = sum_of_numbers + number

but there is a shorter way to do this, and it's represented as:

sum_of_numbers += sum_of_numbers

which will do the same exact thing. In fact this works for any mathematical operation for example:

a *= 3

is the same thing as

a = a * 3

and

a /= 3

is the same thing as

a = a / 3

It's the same thing, but it's a much shorter and more readable notation.

Anyways, this code will go in the for loop to almost finish the code

"

def list_total(numbers):

   sum_of_numbers = 0

   for number in numbers:

       sum_of_numbers += number

"

The last thing is to return this value, and this is simply done by using the syntax:

"return {value here}"

and since the sum_of_numbers has the value, we write

"return sum_of_numbers"

at the end of the function, which is very very important, because when you use the return keyword, you end the function, and return whatever value is next to the return to the function call

So to finish the code we just add this last piece to get:

"

def list_total(numbers):

   sum_of_numbers = 0

   for number in numbers:

       sum_of_numbers += number

   return sum_of_numbers

"

7 0
2 years ago
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