Answer:
b. Acceptance
Explanation:
<em>"Acceptance </em><em>of risk is the choice to do nothing to protect an information asset and to accept the outcome of its potential exploitation. </em><em>"</em>
<em>Acceptance Control </em>is important as a strategy when an organization has accomplished a determined level of risk, or it has estimated potential damages that might happen due to attacks, or the organization has developed a thorough analysis related to cost benefits, or it has also evaluated the probabilities of attacks.
Answer:
1:1
Explanation:
According to my research on different types of relationships between two variables, I can say that based on the information provided within the question the entities PROFESSOR and DEPARTMENT exhibit a 1:1 relationship. In other words there can only be one Professor per Department and vice-versa.
I hope this answered your question. If you have any more questions feel free to ask away at Brainly.
Answer:
- def getCharacterForward(char, key):
- charList = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
-
- if(len(char) > 1):
- return None
- elif(not isinstance(key, int)):
- return -1
- else:
- index = charList.find(char)
- if(index + key <= 25):
- return charList[index + key]
- else:
- return charList[(index + key)% 26]
-
- print(getCharacterForward("C", 4))
- print(getCharacterForward("X", 4))
Explanation:
Firstly, define a charList that includes all uppercase alphabets (Line 2). We presume this program will only handle uppercase characters.
Follow the question requirement and define necessary input validation such as checking if the char is a single character (Line 4). We can do the validation by checking if the length of the char is more than 1, if so, this is not a single character and should return None (Line 5). Next, validate the key by using isinstance function to see if this is an integer. If this is not an integer return -1 (Line 6 - 7).
Otherwise, the program will proceed to find the index of char in the charList using find method (Line 9). Next, we can add the key to index and use the result value to get forwarded character from the charList and return it as output (Line 11).
However, we need to deal a situation that the char is found at close end of the charList and the forward key steps will be out of range of alphabet list. For example the char is X and the key is 4, the four steps forward will result in out of range error. To handle this situation, we can move the last two forward steps from the starting point of the charList. So X move forward 4 will become B. We can implement this logic by having index + key modulus by 26 (Line 13).
We can test the function will passing two sample set of arguments (Line 15 - 16) and we shall get the output as follows:
G
B
Answer:
Both codes are correct.The value of even is true when the number is even.
Explanation:
Code 1:
number %2 ==0 means that when dividing number by 2 is the remainder coming out is zero.If it is true then even becomes is true if it is false then else statement is executes in which even becomes false.Means the number is odd.This code is simple and easy to understand.
Code 2:-
This code is a bit tricky and takes time to understand.even becomes true
when the number is divisible by 0 and false when it is not.
