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Delvig [45]
3 years ago
11

Evaluate the expression. 9.12-5.28÷3.52Answer​

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
7 0

Answer:

=7.62

Step-by-step explanation:

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U need help ASAP!!!Please explain the answer
jolli1 [7]
ANSWER:
V= 3,619.1 km^3

EXPLANATION:
Simply plug in the radius (12 km) and height (24 km) into the cone volume formula.

7 0
3 years ago
John needs 150 feet of rope to section off part of his barn. At a local hardware store he can buy a 30 yard spool for $24 or he
Sphinxa [80]

Answer:

30 yards for 24 vs 1 foot for 25 cents

so lets multiple the yards by 3 to see how many feet

90 feet = 30 yards

90 feet 24 dollars

now lets divide 90 by 24

3.75 so 3.75 per foot

so the second one is way better

Hope This Helps!!!

7 0
2 years ago
Read 2 more answers
What is the equation of the line?
Lelechka [254]
I’m Pretty Sure It’s C.
3 0
3 years ago
If you're ladder is 10 feet long and you place the bottom 6 feet from the wall how far can you reach
-Dominant- [34]
This is like a triangle.
One side, the hypotenuse, is the length of the ladder, 10 feet in this case.
Another side, one of legs, is the distance from the bottom of the ladder to the side of the wall, 6 feet.
The last side is what we need to find, how high up the ladder reaches.

Using the p<span>ythagorean theorem, we can find this third side.
This is written as a^2 + b^2 = c^2.
A and B are the legs, while C is the hypotenuse.

Plugging in known values, we get:
6^2 + b^2 = 10^2

Solve as much as possible:
6^2 = 36
10^2 = 100
36 + b^2 = 100

Now you must isolate b.
Subtract 36 from both sides.
100 - 36 = 64
b^2 = 64

The last step in finding b is doing the inverse of squaring, which is square rooting.
√64 = 8
So b equals 8.

This means that <span>the ladder can reach 8 feet up the wall.</span></span>
6 0
3 years ago
Which equations represent the asymptotes of the hyperbola (x-1)^2/36-(y-2)^2/64=1 ?
allochka39001 [22]

Answer:

4x+3y=10 and  4x-3y=-2

Step-by-step explanation:

The asymptote equation of a translate hyperbola with equation \frac{(x-h)^2}{b^2}-\frac{(y-k)^2}{a^2}=1 is y=\pm\frac{b}{a}(x-h)+k

The given hyperbola has equation: \frac{(x-1)^2}{36}-\frac{(y-2)^2}{64}=1

Or \frac{(x-1)^2}{6^2}-\frac{(y-2)^2}{8^2}=1

Comparing to \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

We have  a=6 and b=8, h=1 and k=2.

We substitute this values to get:

y=\pm\frac{6}{8}(x-1)+2

y=\pm\frac{4}{3}(x-1)+2

3y=\pm4(x-1)+6

We split the plus or minus sign to get:

3y=4x-4+6

3y=4x+2

3y-4x=2

Or

3y=-4(x-1)+6

3y=-4x+4+6

3y+4x=10

5 0
3 years ago
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