Answer:
Greetings!
The correct answer is the last one, "When the future level of some variable is seen as a function other than time".
Explanation:
Along other forecasting methods, the moving average finds utility in cases when seasonality is a factor. This term refers to a set of variables unknown to (or uncontrolled by) the observer that influence the series model in some way.
By applying a moving average to a time series one can mitigate such irregular effects.
I hope this helps!
a) time, t = 11.407 s, b) distance x = 175.66 m, v = c) speed v = 30.80 m / s
<h3>Explanation of question:</h3>
a) This is kinematics exercise, write the equation of each vehicle car is;-
x = x₀ + v₀ t + ½ a t²
Let's fix our the reference system at a point where the car indicate that the car stops from rest is vo = 0.
x₀ = v₀ = 0
<h3>we substitute</h3>
x = ½ a t²
truck
x₂= v₀ t
v₀ = 15.4 m / s
At the point where they are, positions are equal:-
½ a t² = vo t
t = 2 vo / a
calculate us
t = 2 15.4 / 2.
t = 11.407 s
b) the distance to reach it
x = ½ to t²
x = ½ 20 11.407²
x = 175.66 m
c) the speed of the car is
v = vo + a t
vo = 0
v = at
v = 2.0 11.407
v = 30.80 m / s
To know more about acceleration visit:-
brainly.com/question/12550364
#SPJ4
Matter is generally any physical substance, and it's all around us... a form of matter would be liquid, and water is a liquid.
∆S>_closed integral of dQ/T
There are many equations for different situations of entropy but this is a general one
Two resistors in series are often called a 'voltage divider', because the
total voltage divides in proportion to the resistances.
The total resistance in the string across the battery is (11 + 6) = 17 ohms.
-- The full battery voltage appears across 17 ohms.
-- The voltage across the 11-ohms is (11/17) of the battery, and
-- the voltage across the 6-ohms is (6/17) of the battery.
(6/17) x (B) = 9 volts
Multiply each side by (17/6) : B = (9 volts) x (17/6) =<em> 25.5 volts </em>.
By the way, in case you care or are asked . . .
-- The current in the whole series loop is B/R = 25.5 / 17 = 1.5 Amperes
-- The power drawn from the battery is B²/R = (25.5)²/17 = 38.25 watts
-- The power dissipated by the 6-ohm resistor is V²/R = 9²/6 = 13.5 watts
-- The power dissipated by the 11-ohm resistor is I²R = (1.5)² (11) = 24.75W
-- (Check: 13.5W + 24.75W = 38.25W yay! )
-- If they're just composition units hanging out in the air, then both resistors
are getting quite warm.
