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REY [17]
3 years ago
5

If V is the original volume, V' is the new volume, T is the original Kelvin temperature, and T' is the new Kelvin temperature, h

ow is Charles's law expressed mathematically
Physics
1 answer:
madam [21]3 years ago
4 0

Answer:

\frac{V}{T} = \frac{V'}{T'}

Explanation:

Given the following data;

Original volume = V

New volume = V'

Original temperature = T

New temperature = T'

To write an expression for Charles's law;

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles law is given by the formula;

\frac {V}{T} = K

\frac{V}{T} = \frac{V'}{T'}

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A rock is thrown upward with a velocity of 18 meters per second from the top of a 38 meter high cliff, and it misses the cliff o
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The rock would be at a point 12 m from water at a time <u>4.8 s</u>.

Take the origin of the coordinate system at the top of the cliff. It is thrown upwards with a velocity u. When the rock is at a point 12 m from water, calculate the vertical displacement of the rock from the origin.

y= -38m- (-12 m)=-26 m

Use the equation of motion,

y=ut +\frac{1}{2} at^2

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Substitute 18 m/s for u, -26 m for y and -9.8 m/s² for a=g.

y=ut +\frac{1}{2} at^2\\ (-26 m)=(18m/s)t+\frac{1}{2}(-9.8m/s^2)t^2

Solve the quadratic equation for t.

t=\frac{(18m/s)(+/-)\sqrt{(18m/s)^2-4(4.9m/s^2)(-26m)} }{2(4.9m/s^2)}

Taking only the positive value,

t=\frac{(18 m/s)+(28.87 m/s)}{9.8 m/s^2)} \\ t=4.78 s

After a time of <u>4.8 s</u> the rock would be at a distance of 12 m from water.

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