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3 years ago

5

If V is the original volume, V' is the new volume, T is the original Kelvin temperature, and T' is the new Kelvin temperature, h

ow is Charles's law expressed mathematically

1 answer:

madam [21]3 years ago

4 0

Answer:

$\frac{V}{T} = \frac{V'}{T'}$

Explanation:

Given the following data;

Original volume = V

New volume = V'

Original temperature = T

New temperature = T'

To write an expression for Charles's law;

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles law is given by the formula;

$\frac {V}{T} = K$

$\frac{V}{T} = \frac{V'}{T'}$

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What is the minimum coeffecient of static friction μmin required between the ladder and the ground so that the ladder does not s

mars1129 [50]

Answer:

$\mu = \frac{1}{2tan\theta}$

Explanation:

let the ladder is of mass "m" and standing at an angle with the ground

So here by horizontal force balance we will have

$\mu N_1 = N_2$

by vertical force balance we have

$N_1 = mg$

now by torque balance about contact point on ground we will have

$mg(\frac{L}{2}cos\theta) = N_2(L sin\theta)$

so we will have

$N_2 = \frac{mg}{2tan\theta}$

now from first equation we have

$\mu (mg) = \frac{mg}{2tan\theta}$

$\mu = \frac{1}{2tan\theta}$

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3 years ago

What is solid matter and can we covert matter into something else

lbvjy [14]

Answer: Solid matter is one of the three main states of matter, along with liquid and gas. Matter is the "stuff" of the universe, the atoms, molecules and ions that make up all physical substances. In a solid, these particles are packed closely together and are not free to move about within the substance.

All matter exists as solids, liquids, or gases. These are called the states of matter. Matter can change from one state to another if heated or cooled. If ice (a solid) is heated it changes to water (a liquid).

Explanation:

6 0

3 years ago

PLEASE ANSWER ASAP BEFORE MY TEACHER AND MY MOM KILLES ME PLEASE ASAP

alisha [4.7K]

Answer:

There are 4 liquids in this experiment and red is the least dense of all of them so it should float on top, which it is doing.

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4 0

3 years ago

Read 2 more answers

Two ice skaters collide on the ice. A 39.6-kg skater moving South at 6.21 m/s collides with a 52.1-kg skater moving East at 4.33

Stells [14]

Answer:

V = 3.6385 m/s

θ = 47.46 degrees

Explanation:

the important data in the question is:

Skater 1:

$M_1$ = 39.6 kg

direction: south (axis y)

$V_{1iy}$ = 6.21 m/s

Skater 2:

$M_2$ = 52.1 kg

direction: east (axis x)

$V_{2ix}$ = 4.33 m/s

Now using the law of the conservation of linear momentum ( $P_i = P_f$ and knowing that the collision is inelastic we can do the next equations:

$M_{1}V_{1ix}+M_2V_{2ix} = V_{sx}(M_1+M_2)$ (eq. 1)

$M_{1}V_{1iy}+M_2V_{2iy} = V_{sy}(M_1+M_2)$ (eq. 2)

Where $V_{sx}$ and $V_{sy}$ is the velocity of the sistem in x and y after the collision.

Note: the conservation of the linear momentum have to be make once by each axis.

Now, in the (eq. 1) the skater 1 don't have velocity in the axis x, so we can replace $V_{1ix}$ by 0 in the equation and get:

$M_2V_{2ix} = V_{sx}(M_1+M_2)$ (eq. 1)

also, in the (eq. 2) the skater 2 don't have velocity in the axis y, so we can replace $V_{2iy}$ by 0 in the equation and get:

$M_{1}V_{1iy} = V_{sy}(M_1+M_2)$ (eq. 2)

Now, we just replace the data in both equations:

$(52.1)(4.33) = V_{sx}(39.6+52.1)$ (eq. 1)

$(39.6)(6.21) = V_{sy}(39.6+52.1)$ (eq. 2)

solving for $V_{sx]$ and $V_{sy}$ we have:

$V_{sx]$ = 2.46 m/s

$V_{sy]$ = 2.681 m/s

using the pythagoras theorem we can find the magnitude of the velocity as:

V = $\sqrt{2.46^2+2.681^2}$

V = 3.6385 m/s

For find the direction we just need to do this;

θ = $tan^{-1}(\frac{2.681}{1.46})$

θ = 47.46 degrees

3 0

3 years ago

Nabil wants to work out the density of a pebble. he has a displacement can and a beaker. What other piece of equipment will he n

Svetllana [295]

Answer:

1) Measuring cylinder

2) Top Pan Balance

Explanation:

To find the density of the pebble Nabil should first accurately measure the mass of the pebble using the top pan balance

He should then fill the displacement can till the water reaches the outlet pipe at the to of the cylinder

He should then place the pebble into the cylinder carefully ans allow the water that would start coming out to stop

The volume of water in the displaced cylinder is then measured and the density is found by dividing the mass of the pebble by the volume of water in the measuring cylinder

$Density \ of \ pebble = \dfrac{Pebble \ mass}{Volume \ of \ water \ in\ the \ measuring \ cylinder} = \dfrac{Pebble \ mass}{Water \ volume \ displaced}$

3 0

3 years ago