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REY [17]
3 years ago
5

If V is the original volume, V' is the new volume, T is the original Kelvin temperature, and T' is the new Kelvin temperature, h

ow is Charles's law expressed mathematically
Physics
1 answer:
madam [21]3 years ago
4 0

Answer:

\frac{V}{T} = \frac{V'}{T'}

Explanation:

Given the following data;

Original volume = V

New volume = V'

Original temperature = T

New temperature = T'

To write an expression for Charles's law;

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles law is given by the formula;

\frac {V}{T} = K

\frac{V}{T} = \frac{V'}{T'}

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If a force of 1.0 N pulled up and parallel to the surface of the incline is required to raise the mass back to the top of the in
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The question is incomplete! The complete question along with answer and explanation is provided below.

Question:

A 0.5 kg mass moves 40 centimeters up the incline shown in the figure below. The vertical height of the incline is 7 centimeters.

What is the change in the potential energy (in Joules) of the mass as it goes up the incline?  

If a force of 1.0 N pulled up and parallel to the surface of the incline is required to raise the mass back to the top of the incline, how much work is done by that force?

Given Information:  

Mass = m = 0.5 kg

Horizontal distance = d = 40 cm = 0.4 m

Vertical distance = h = 7 cm = 0.07 m

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Required Information:  

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Work done = 0.39 N.m

Explanation:

The potential energy is given by

PE = mgh

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PE = 0.5*9.8*0.07

PE = 0.343 Joules

As you can see in the attached image

sinθ = opposite/hypotenuse

sinθ = 0.07/0.4

θ = sin⁻¹(0.07/0.4)

θ = 10.078°

The horizontal component of the normal force is given by

Fx = Fncos(θ)

Fx = 1*cos(10.078)

Fx = 0.984 N

Work done is given by

W = Fxd

where d is the horizontal distance

W = 0.984*0.4

W = 0.39 N.m

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