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MrMuchimi
3 years ago
15

On a basketball team, the following players made most of the 56 points made during the last basketball game.

Mathematics
1 answer:
Ivanshal [37]3 years ago
4 0

Answer:

7.75

Step-by-step explanation:

56-27-21-0.25=7.75

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There are 158 students registered for American History classes. There are twice as many students registered in second period as
Margarita [4]

There are 28 students in first period and 56 students in sceond period and 74 students in third period

<em><u>Solution:</u></em>

Let the number of students in first period be "x"

Let the number of students in second period be "y"

Let the number of students in third period be "z"

<em><u>There are 158 students registered for American History classes.</u></em>

Therefore,

x + y + z = 158 ---------- eqn 1

<em><u>There are twice as many students registered in second period as first period</u></em>

number of students in second period = twice of number of students in first period

y = 2x ------- eqn 2

<em><u>There are 10 less than three times as many students in third period as in first period</u></em>

number of students in third period = 3 times number of students in first period - 10

z = 3x - 10 ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

x + 2x + 3x - 10 = 158

6x = 168

<h3>x = 28</h3>

<em><u>Substitute x = 28 in eqn 2</u></em>

y = 2(28)

<h3>y = 56</h3>

<em><u>Substitute x = 28 in eqn 3</u></em>

z = 3(28) - 10

z = 84 - 10

<h3>z = 74</h3>

Thus there are 28 students in first period and 56 students in sceond period and 74 students in third period

5 0
3 years ago
Multiply: (-1-3i)(-5 - 4i)
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The answer is -7+19i because of the procedure used in math
6 0
2 years ago
Can someone help? At least solve one that you might know, explain if you can.
Sladkaya [172]
The awnser for question 5 is 4/6
7 0
3 years ago
(5a-5)(2a+2)<br> Find each product
weeeeeb [17]
(<span>5a-5)(2a+2)
= 5a*2a -5*2a + 2*5a - 5*2
= 10a^2  - 10a + 10a  - 10
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The product of the equation is </span>10a^2 - 10
6 0
3 years ago
Read 2 more answers
Thulani goes to the library every 7 days. He goes to the market every 4 days
emmasim [6.3K]

Thulani goes to both the library and the market for 5 more times during the year.

Step-by-step explanation:

Thulani goes to the library every 7 days. He goes to the market every 4 days.

We have to calculate the Least Common Multiple (LCM) to analyze the next common day on which he will go to both places.

The factors of 7 are:  1 x 7

The factors of 4 are: 2 x 2

Therefore, the LCM would be = 1 x 7 x 2 x 2

LCM = 28

LCM indicates that Thulani will go to both places on every 28th day.

To calculate the number of times (n) he will go to both places on same day. We can use the formula mentioned below:'

n = \frac{Number of days}{frequency}

Here frequency represents the LCM = 28.

The number of days are:

August: 30 (we are excluding 1st August)

September: 30

October: 31

November: 30

December: 31

Total  = 152

By putting the values in formula, we get

n = \frac{152}{28}

n = 5.42

As, the number of times can only be a whole number. Therefore, Thulani goes to both the library and the market for 5 more times during the year.

Learn more:

The following links have more information

brainly.com/question/12419898

brainly.com/question/12764620

Keywords: LCM, same day

#learnwithBrainly

7 0
3 years ago
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