Set of equations that can be used to calculate rate for each plumber:
2A+8B+8C = 1,400 --- (1)
4A+7B+10C = 1,660 --- (2)
3A+9B+9C = 1,660 --- (3)
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2*(1) - (2)
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4A+16B+16C = 2,800
4A+7B+10C = 1,660 -
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9B+6C = 1,140 --- (4)
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3(2) -4(3)
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12A+21B+30C = 4,980
12A+36B+36C = 6,600 -
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-15B-6C = -1,620 --- (5)
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(4) + (5)
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9B+6C = 1140
-15B-6C = -1620 +
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-6B = -480 => 6B = 480 => B = 480/6 = 80
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Using (4), 9(80)+6C = 1140
720+6C = 1140 => 6C = 1140-720 = 420 => C = 420/6 = 70
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Using (1), 2A+8(80)+8(70) = 1400
2A+640+560 =1400 => 2A = 1400-640-560 = 200 => A = 200/2 = 100
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The rates are:
A = $100
B = $80
C = $70
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On Thursday, number of calls: A = 4 hrs, B = 6 hrs, C = 3 hrs
Money earned = 4*100+6*80+3*70 = $1,090
100% of Kerion's paper squares are:
(100% / 100%) = 1
Half of the squares of your paper are colored blue:
(1) / (2) = 1/2
Of the blue squares, 1/3 of them will also have stripes:
(1/2) * (1/3) = 1/6
answer
A fraction of (1/6) squares will be blue with strips
Answer:
Step-by-step explanation:
We are given the following in the question:
Quantity, q
Selling price in dollars per yard, p
Total revenue earned =
f(20)=13000
This means that 13000 yards of fabric is sold when the selling price is 20 dollars per yard.
f′(20)=−550
This means that increasing the selling price by 1 dollar per yards there is a decrease in fabric sales by 550.
We have to find R'(20)
Differentiating the above expression, we have,
Putting the values, we get,
Answer:
I think it might be 30pi m or 94.2 m.
Step-by-step explanation: So you are finding the perimeter of the circle. You have a radius of 15, the perimeter for a circle is C=2pir. Now we can do C=2pi(15). The answer is 30pi or C=2 x 3.14 x 15= 94.2 Hope this helps.
<h3>
Answer: Independent</h3>
For two events A and B, if the occurrence of either event in no way affects the probability of the occurrence of the other event, then the two events are considered to be <u> independent </u> events.
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Explanation:
Consider the idea of flipping a coin and rolling a dice. If these actions are separate (i.e. they don't bump into each other), then one object won't affect the other. Hence, one probability won't change the other. We consider these events to be independent.
In contrast, let's say we're pulling out cards from a deck. If we don't put the first card back, then the future probabilities of other cards will change. This is considered dependent.
