The length and width of the rectangular box are 13 ft and 6 ft respectively.
<h3>How to find the length and width of a rectangle?</h3>
The length of the batter's box on a softball field is 1 ft more than twice the width.
The area of the batter's box is 78 ft².
The length and width of the rectangular batter's box can be found as follows:
Therefore,
area of a rectangle = lw
where
Therefore,
area of the rectangular box = 78 ft²
l = 1 + 2w
Hence,
78 = (1 + 2w)w
78 = w + 2w²
2w² + w - 78 = 0
Hence,
w = 6 and w = -13 /2
we can only use positive values.
Therefore,
width = 6 ft
length = 2(6) + 1 = 13 ft
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–2x + 4y = –7 . . . . . (1)
y = -1/2x + 5 . . . . . . (2)
Putting (2) into (1), we have:
-2x + 4(-1/2x + 5) = -7
-2x - 2x + 5 = -7
-4x = -7 - 5 = -12
x = -12/-4 = 3
y = -1/2(3) + 5 = -3/2 + 5 = 7/2
Hence, the system has one solution.
Answer:
i got 45
Step-by-step explanation:
