Answer:
3x^2
Step-by-step explanation:
Given:
(3x) * {(1/x)^-4 }* (x^-3)
=(3x) * {1 ÷ (1/x)^4} * {1/x^3}
=(3x) * {1(x/1)^4} * (1/x^3)
=(3x) * (x^4) * (1/x^3)
=(3x) (x^4) (1) / x^3
Multiply the denominators
=3x^5 / x^3
Can also be written as
=3*x*x*x*x*x / x*x*x
Divide the x
= 3*x*x / 1
=3x^2
Answer:
See below.
Step-by-step explanation:
I'll work it out myself, then we should be able to see the mistake:-
6 ∛ (64x^5y^9)
= 6 * 4 * x^(5/3) * y^3
= 24 x^(3/3) * x^(2/3) y^3
= 24 x y^3 ∛(x^2)
You've got confused withe the cube root (∛) on the first line. You've interpreted it as ' 3 times the square root' so you were on the wrong road from the beginning.
Note that y^9 has cube root y^(9/ 3) = y^3 and x^5 has cube root of x^(5/3). The square root of x^9 is x^(9/2).
The given expression is : (4x – 7.2) + (-5.3x-8)
Simplify :
Open the brackets :
(4x – 7.2) + (-5.3x-8) = 4x - 7.2 - 5.3x - 8
Arrange the variable and constant terms together :
(4x – 7.2) + (-5.3x-8) = 4x - 5.3x - 8 - 7.2
Solve the variable and constant terms together :
(4x – 7.2) + (-5.3x-8) = - 1.3x - 15.2
Since, the variable and constant term can not solve together so the above equation is the simplest form:
(4x – 7.2) + (-5.3x-8) = - 1.3x - 15.2
Answer : (4x – 7.2) + (-5.3x-8) = - 1.3x - 15.2
Answer:
c
Step-by-step explanation:
