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Brilliant_brown [7]
4 years ago
7

Find the length of arcAB. *

Mathematics
1 answer:
Naddik [55]4 years ago
4 0

I hope this helps you

You might be interested in
How do you do this simultaneous equation?
tatiyna
The y is the same for both equations. Equate them
-x - 5 = 2x + 4 Add x to both sides
- 5 = 3x + 4 Subtract 4 from both sides.
- 9 = 3x Divide by 3
x = -9 / 3
x = - 3

y = - x - 5
y = -(-3) - 5
y = - 2

So that point is where the two equations meet.

To see the graph of your question on the internet, go to 
Wolframalpha.com 
and put this string in the question space.
y = -x - 5; y  = 2x + 4  Note the semi colon in the middle.

To the moderator: This is my own work. I'm using Wolfram to get the answer.
5 0
3 years ago
Seven tenths of a number plus 14 is less than forty-nine
Virty [35]
7/10n + 14 = 49
7/10n = 35
n = 35 x 10/7
n = 50
7 0
3 years ago
3(b - 15) =9 solve for b
shepuryov [24]
B = 18 because 18-5 is equal to 3 and 3x3 is equal to 9.
4 0
3 years ago
Can someone pls pls help me?
vesna_86 [32]

Answer:

Hello! answer: 9

Step-by-step explanation:

Formula for triangle area: base × height ÷ 2 or base × height × 1/2

6 × 3 = 18 18 ÷ 2 = 9 therefore 9 is the area!

8 0
3 years ago
The region bounded by y=(3x)^(1/2), y=3x-6, y=0
Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is y = (3x)^{\frac{1}{2} }

⇒ y^{2} = 3x ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

y^{2} - y - 6 = 0

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = \int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx

= \sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}

= [\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} }  }{3}] - [13.5 - 18 - 6 + 12]

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0
3 years ago
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